Answer:
3 mol AlCl₃.
Explanation:
Hello!
In this case, according to the specified reactants and products, it is possible to set up the following balanced chemical reaction:
Whereas we evidence the 1:3 mole ratio between aluminum nitrate and sodium chloride; thus, since different moles were reacting, we need to identify the limiting reactant by computing the moles of AlCl₃ produced by each reactant as follows:
Thus, we infer that NaCl is the limiting reactant as it produces the fewest moles of AlCl₃; consequently the produced amount of this product is 3 mol.
Best regards!
N2 H2 ——> NH3
Add a 3 in front of H2 and a 2 in front of NH3
So the answer would be
N2 3H2 ——> 2NH3
I don’t know this, so I did research, so here! This is from a website called “Quora”, btw!
If you need more information, just go to this app by copying and pasting your question on the G o o g l e Search bar!
It looks like you have to watch the videos linked (i think you need to click on the names of animals). for each video, right down the traits and functions of the animal.
Answer:
The answer to your question is: letter D
Explanation:
Data
Isotope mass 1 = 54 amu
Isotope mass 2 = 56 amu
Atomic weight = 54.37 amu
Percent abundance of isotope 2 = ? = X
Percent abundance of isotope 1 = 1 - x
Formula
Atomic weight = (Mass isotope 1)(1 - x) + (mass isotope 2)(x)
Process
Place the data in the formula and solve for x.
54.37 = 54( 1 - x) + 56x
54.37 = 54 - 54x + 56x
54.37 - 54 = -54x + 56x
0.37 = 2x
x = 0.37 / 2
x = 0.185
To find the percent multiply by 100
x = 0.185 x 100
x = 18.5 % = Mass of isotope 2
Mass of isotope 1 = 100 - 18.5 = 81.5 %
