<span>Starch and
cellulose have the same substance but different structures. They are both
polysaccharides. The basic unit of a polysaccharide is the glucose. Glucose,
which contains carbon, hydrogen, and oxygen, have two forms. The alpha-glucose
with an alcohol group attached to carbon 1 is down and the beta-glucose with
the alcohol group attached to carbon 1 is up. Starch is the alpha-glucose while
cellulose is the beta-glucose. Starches are linked into a straight chain whereas
the cellulose are connected like a pile of stack paper. When the human body
eats starch, it can digest the starch but not the cellulose because it has no
enzyme that can break it down. </span>
Answer:
A carbohydrate is a compound composed of molecules of carbon (C), hydrogen (H), and oxygen (O) such that its general chemical formula is .
Biochemical functions of carbohydrates: Carbohydrates provide Stored Energy, Carbohydrates help to preserve Muscle and promote digestive health and Carbohydrates build macromolecules
Explanation:
A carbohydrate is a compound composed of molecules of carbon (C), hydrogen (H), and oxygen (O) such that its general chemical formula is .
Biochemical functions of carbohydrates:
1. Carbohydrates provide Stored Energy.
2. Carbohydrates help to preserve Muscle and promote digestive health.
3. Carbohydrates build macromolecules
Answer:
METHANE IS COMPARITIVELY LESS TOXIC AND INFLAMMABLE S COMPARED TO OTHER LABORATORY USED GASES.
Explanation:
THEREFORE,IT CAN BE USED IN THE LABS DUE TO IT'S LESS TOXICITY AND USAGE IN EXPERIMENTS.
Answer:
The number of neutrons present in one atom of isotope of Silicon of mass 28 amu is<u> 14 neutrons</u>
Explanation:
Symbol of Si isotope
<u>Number of Neutron = Mass number - Atomic Number</u>
Mass number = Total number of protons and neutrons present in the nucleus of the atom.For Si = 28 amu
Atomic Number = Total number of Protons present in the nucleus.
Si = 14
Number of neutron = 24 - 14
= 14
Answer:
Deduce the balanced chemical equation:
CaCO3(s) + 2HCl(aq) > CaCl2 + H2O(l) + CO2(g)
2. Write as ionic species:
Ca2+(aq) + CO3 2- (aq) + 2H+ + 2Cl- > Ca2+(aq)+ 2Cl-(aq) + H2O(l) + CO2(g)
3. Identify ions on the right that also appear on the left, and eliminate them. (As Robert Cruikshank says, these are known as ’spectator ions’ and take no overall part in the reaction):
CO3 2- (aq) + 2H+(aq) > H2O(l) + CO2(g)
This is the balanced ionic equation.