15.63 mol. You need 15.63 mol HgO to produce 250.0 g O_2.
<em>Step 1</em>. Convert <em>grams of O_2 to moles of O_2</em>
Moles of O_2 = 250.0 g O_2 × (1 mol O_2/32.00 g O_2) = 7.8125 mol O_2
<em>Step 2</em>. Use the molar ratio of HgO:O_2 to convert <em>moles of O_2 to moles of HgO
</em>
Moles of HgO = 0.8885 mol O_2 × (2 mol HgO/1 mol O_2) = <em>15.63 mol HgO</em>
I would say all if no statements are available
Elapsed time
Time Graphs. Set the Type of graph menu to position vs. time and the Choose a graph menu to position graph 1. This means that the vertical axis represents the position, or location, of the caterpillar along the ground, while the horizontal axis represents the elapsed time.
