Answer:
-28
Step-by-step explanation:
6 2/3*-4 1/5=
20/3*-21/5=
4/3*-21/1=
4/1*-7/1=
-28
Information about concavity is contained in the second derivative of a function. Given f(x) = ax² + bx + c, we have
f'(x) = 2ax + b
and
f''(x) = 2a
Concavity changes at a function's inflection points, which can occur wherever the second derivative is zero or undefined. In this case, since a ≠ 0, the function's concavity is uniform over its entire domain.
(i) f is concave up when f'' > 0, which occurs when a > 0.
(ii) f is concave down when f'' < 0, and this is the case if a < 0.
In Mathematica, define f by entering
f[x_] := a*x^2 + b*x + c
Then solve for intervals over which the second derivative is positive or negative, respectively, using
Reduce[f''[x] > 0, x]
Reduce[f''[x] < 0, x]
The first one would be 1/2 or .5 the second one is 8 because -3+11 is 8 the third is -9/10 because you do the c hook method for mixed fractions 4th is -3 and the 5th one is -1.1
Answer:
12
Step-by-step explanation:
sqrt(6*24)
sqrt(144)
sqrt(12*12)
12
