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Dmitry [639]
3 years ago
12

8. A 12kg bowling ball has a velocity of 8 m/s, and is brought to

Physics
1 answer:
Natali5045456 [20]3 years ago
8 0

Answer:

The change in momentum experienced by the bowling ball is 96 kgm/s.

Explanation:

Given;

mass of the bowling ball, m = 12 kg

velocity of the bowling ball, v = 8 m/s

time  of motion, t = 10 s

The change in momentum experienced by the bowling ball is equal to the impulse experienced by the bowling ball.

ΔP = J = F x t

J = ft =\frac{mv}{t} \times t = mv\\\\J = 12 \times 8\\\\J = 96 \ kg.m/s

Therefore, the change in momentum experienced by the bowling ball is 96 kgm/s.

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3 years ago
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Steam enters a counterflow heat exchanger operating at steady state at 0.07 MPa with a specific enthalpy of 2431.6 kJ/kg and exi
PIT_PIT [208]

Answer:

Explanation:

Given:

Steam Mass rate, ms = 1.5 kg/min

= 1.5 kg/min × 1 min/60 sec

= 0.025 kg/s

Air Mass rate, ma = 100 kg/min

= 100 kg/min × 1 min/60 sec

= 1.67 kg/s

A.

Extracting the specific enthalpy and temperature values from property table of “Saturated water – Pressure table” which corresponds to temperature at 0.07 MPa.

xf, quality = 0.9.

Tsat = 89.9°C

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hfg = 2283.38 kJ/kg

Using the equation for specific enthalpy,

hi = hf + (hfg × xf)

= 376.57 + (2283.38 × 0.9)

= 2431.552 kJ/kg

The specific enthalpy of the outlet, h2 = hf

= 376.57 kJ/kg

B.

Rate of enthalpy (heat exchange), Q = mass rate, ms × change in specific enthalpy

= ms × (hi - h2)

= 0.025 × (2431.552 - 376.57)

= 0.025 × 2055.042

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5 0
3 years ago
An unknown substance has a mass of 15 g and a volume of 4 cm3. Calculate the density of the unknown substance.
myrzilka [38]

Answer:

Density is 3.75g/cm3

Explanation:

Density = mass ÷ volume

= 15g ÷ 4cm3

= 3.75g/cm3

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3 years ago
A soccer player kicks a ball horizontally at 28 m/s from a bridge and hits the ground after 1.5 s. What is the range of the ball
Lelu [443]

Answer:

42

Explanation:

range of ball = u×t

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2 years ago
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