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3 years ago

13

If 5 mL of stomach acid (pH=2) is pushed up into your throat, how many grams of Tums should you take to completely react with th

e stomach acid?
The balanced reaction of stomach acid with Tums is:
CaCO3 + 2HCl = CO2 + H2O + CaCl2

1 answer:

zzz [600]3 years ago

8 0

Answer:

4 i think

Explanation:

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In the bromination reaction of trans-cinnamic acid, a student started with 300 mg oftrans-cinnamic acid and excess bromine. T

jonny [76]

Answer:

The percentage yield is= 80%

Explanation:

% yield= actual yield/theoretical yield ×100

From The question

Actual yield= 240mg

Theoretical yield= 300mg

%yield= 240/300×100= 80%

3 0

3 years ago

A certain liquid has a normal freezing point of and a freezing point depression constant . Calculate the freezing point of a sol

katrin2010 [14]

The question is incomplete, the complete question is:

A certain liquid X has a normal freezing point of $0.80^oC$ and a freezing point depression constant $K_f=7.82^oC.kg/mol$ . Calculate the freezing point of a solution made of 81.1 g of iron(III) chloride () dissolved in 850. g of X. Round your answer to significant digits.

<u>Answer:</u> The freezing point of the solution is $-17.6^oC$

<u>Explanation:</u>

Depression in the freezing point is defined as the difference between the freezing point of the pure solvent and the freezing point of the solution.

The expression for the calculation of depression in freezing point is:

$\text{Freezing point of pure solvent}-\text{freezing point of solution}=i\times K_f\times m$

OR

$\text{Freezing point of pure solvent}-\text{Freezing point of solution}=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times w_{solvent}\text{(in g)}}$ ......(1)

where,

Freezing point of pure solvent = $0.80^oC$

Freezing point of solution = $?^oC$

i = Vant Hoff factor = 4 (for iron (III) chloride as 4 ions are produced in the reaction)

$K_f$ = freezing point depression constant = $7.82^oC/m$

$m_{solute}$ = Given mass of solute (iron (III) chloride) = 81.1 g

$M_{solute}$ = Molar mass of solute (iron (III) chloride) = 162.2 g/mol

$w_{solvent}$ = Mass of solvent (X) = 850. g

Putting values in equation 1, we get:

$0.8-(\text{Freezing point of solution})=4\times 7.82\times \frac{81.1\times 1000}{162.2\times 850}\\\\\text{Freezing point of solution}=[0.8-18.4]^oC\\\\\text{Freezing point of solution}=-17.6^oC$

Hence, the freezing point of the solution is $-17.6^oC$

6 0

2 years ago

If 20.0g of water at 56.2℃ absorbs 195 J of heat, what is the final temperature? *

Gnom [1K]

Answer

Explanation:

rr

3 0

2 years ago

Pt 2. Chem Reactions 50 PTS

Dahasolnce [82]

The red colour is the limiting reactant.

Red-blue colour ball and two white balls attached together are reactants.

Red-blue colour ball and two white and one red colour ball attached to each other are products.

<h3>What is a limiting reagent?</h3>

The reactant that is entirely used up in a reaction is called a limiting reagent.

A reactant is a substance that is present at the start of a chemical reaction. The substance(s) to the right of the arrow are called products.

A product is a substance that is present at the end of a chemical reaction.

Hence,

The red colour is the limiting reactant.

Red-blue colour ball and two white balls attached together are reactants.

Red-blue colour ball and two white and one red colour ball attached to each other are products.

Learn more about limiting reagents here:

brainly.com/question/26905271

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6 0

1 year ago

why is it much easier for group 14 elements to become stable by sharing instead of transferring electrons9

Effectus [21]

Because they are closer to the farther end of the periodic table. Since they are closer to the farther end they don't want to give away their electrons because it would be easier for them to just steal them from other atoms.

5 0

3 years ago

Read 2 more answers