Question

2. A sample of gas has a pressure of 861.05 kPa at a temperature of 25°C. What temperature is required to

Answer 1

Answer:

The final temperature is 414.34 degrees Celsius.

Explanation:

Gay-Lussac's law gives the relation between pressure and temperature. It states that at constant volume, pressure is directly proportional to the temperature of the gas.

$P\propto T$

We have,

Initial pressure, $P_1=861.05\ kPa$

Initial temperature, $T_1=25^{\circ} C= 298.15\ K$

Final pressure, $P_2=1985.48\ kPa$

It is required to find new temperature, using Gay-Lussac's law as:

$\dfrac{P_1}{P_2}=\dfrac{T_1}{T_2}$

$T_2=\dfrac{P_2T_1}{P_1}\\\\T_2=\dfrac{1985.48\times 298.15}{861.05}\\\\T_2=687.49\ K$

or

$T_2=414.34^{\circ} C$

So, the final temperature is 414.34 degrees Celsius.