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Margaret [11]
3 years ago
15

How are domains arranged in materials that are magnetic and in ones that are not

Physics
1 answer:
Valentin [98]3 years ago
8 0

Answer:

In most materials, atoms are arranged in such a way that the magnetic orientation of one electron cancels out the orientation of another

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Read 2 more answers
A billiard ball moving at 5 m/s strikes another ball which is initially at rest. After the collision, the first ball moves at a
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Answer:

The velocity of the second ball is approximately 2.588 m/s

The angle direction of the second ball is 75° counterclockwise from the horizontal

Explanation:

The initial velocity of the first billiard ball = 5 m/s

The initial velocity of the billiard ball the first billiard ball strikes = 0 m/s

The final velocity of the first billiard ball = 4.35 m/s

The final direction of motion of the first billiard ball = 30° below its original motion

For perfectly elastic collision, whereby the target is at rest initially, by conservation of momentum, we have;

m₁ × \underset{v_1}{\rightarrow} = m₁·\underset{v'_1}{\rightarrow} + m₂·\underset{v'_2}{\rightarrow}

Which gives;

m₁ × 5·i = m₁·((√3)/2×5·i - 2.5·j) + m₂·\underset{v'_2}{\rightarrow}

∴ m₂·\underset{v'_2}{\rightarrow} = m₁ × 5·i - m₁·((√3)/2×5·i - 2.5·j)

m₂·\underset{v'_2}{\rightarrow} = m₁ × 5·(1 - √3/2)·i + m₁·2.5·j = m₁ × 2.5·(2 - √3)·i + m₁·2.5·j

Therefore, given that the mass of both billiard balls are equal, we have, m₁ = m₂, which gives;

m₂·\underset{v'_2}{\rightarrow} = m₁·\underset{v'_2}{\rightarrow}  = m₁ × 2.5·(2 - √3)·i + m₁·2.5·j

∴ \underset{v'_2}{\rightarrow} = 2.5·(2 - √3)·i + 2.5·j

The magnitude of the velocity of the second ball is \underset{v'_2}{\rightarrow} = √((2.5·(2 - √3))² + 2.5²) ≈ 2.588 m/s

The direction of the second ball, θ = arctan(2.5/((2.5·(2 - √3))) = 75° counterclockwise from the horizontal.

3 0
3 years ago
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