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BARSIC [14]
3 years ago
13

A 1/4" nut driver with a 1.52 inch diameter handle is used to install a 14" 6 UNC

Engineering
1 answer:
-Dominant- [34]3 years ago
6 0

Answer:

2.23

Explanation:

so wee add

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(10 points) A single crystal in the titanium cable is oriented so that the [001] direction is parallel to the applied load. If t
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Do all websites use the same coding to create?
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3 years ago
The lift on a spinning circular cylinder in a freestream with a velocity of 30 m/s and at standard sea level conditions is 6 N/m
Evgesh-ka [11]

Answer:

The circulation around the cylinder is 0.163 \frac{m^{2} }{s}

Explanation:

Given :

Velocity of spinning cylinder v = 30 \frac{m}{s}

Sea level density \rho = 1.23 \frac{kg}{m^{3} }

Sea level span L = 6 \frac{N}{m}

Lift per unit circulation is given by,

  L = \rho v c

Where c = circulation around cylinder

   c = \frac{L}{\rho v}

   c = \frac{6}{1.23 \times 30}

   c = 0.163 \frac{m^{2} }{s}

Therefore, the circulation around the cylinder is 0.163 \frac{m^{2} }{s}

5 0
4 years ago
The mass flow rate in a 4.0-m wide, 2.0-m deep channel is 4000 kg/s of water. If the velocity distribution in the channel is lin
IceJOKER [234]

Answer:

V = 0.5 m/s

Explanation:

given data:

width of channel =  4 m

depth of channel = 2 m

mass flow rate = 4000 kg/s = 4 m3/s

we know that mass flow rate is given as

\dot{m}=\rho AV

Putting all the value to get the velocity of the flow

\frac{\dot{m}}{\rho A} = V

V = \frac{4000}{1000*4*2}

V = 0.5 m/s

4 0
3 years ago
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