Answer:
Applied Stress > 58.29 MPa
Explanation:
- Resolved shear stress should be greater than critically resolved shear stress in order to cause the single crystal to yield
Given angles are
∅ = 42.7 degree
Ф = 48.3 degree
Critically resolved shear stress = 28.5 MPa
If we consider
Critically resolved shear stress = resolved shear stress
Applied stress can be found by
(1)
Applied Stress =
Applied Stress =
Applied Stress = 58.29 MPa
We got reference
- By putting applied stress values of greater than 58.29 MPa in equation 1 we get
Resolved Shear Stress = 60 x Cos(48.3) x Cos(42.7)
Resolved Shear Stress = 29.33 MPa
Therefore, by the above calculation we conclude that applied stress should be greater than 58.29 MPa, In order to make resolved shear stress to be greater than critically resolved shear stress that is essential for single crystal to yield.
Answer:
a. Heat removal rate will increase
b. Heat removal rate will decrease
Explanation:
Given that
One end of rod is connected to the furnace and rod is long.So this rod can be treated as infinite long fin.
We know that heat transfer in fin given as follows
We know that area
Now when diameter will triples then :
So the new heat transfer will increase by 3 times.
Now when copper rod will replace by aluminium rod :
As we know that thermal conductivity(K) of Aluminium is low as compare to Copper .It means that heat transfer will decreases.
Answer:
The meole fraction of acetone in the outlet liquid is
Explanation:
1.
The schematic diagram to represent this process is shown in the diagram attached below:
2.
the mole fraction of acetone in the outlet liquid is determined as follows:
solute from Basis Gas flow rate
Let the entering mole be : % = 0.012
Let the outlet gas concentration be = 0.1% = 0.001
Thus; the mole fraction of acetone in the outlet liquid is:
The mole fraction of acetone in the outlet liquid is
Answer:
the percentage of light that gets through this combination is 9.38
Explanation:
Given the data in the question;
Let us represent the incident unpolarized light with .
So, the amount of light intensity passing through the first polarizer will be;
= / 2 ------ let this be equation 1
An the amount of light intensity passing through the second polarizer will be;
= cos²θ
given that; the second one has its transmission axis at 30°
so, we substitute;
= × cos²( 30° )
= × 0.75
= 0.75
from equation; = / 2
= 0.75( / 2 )
= 0.375 .
Now, the amount of light intensity passing through the third polarizer will be;
= cos² ( 90° - 30° )
= × cos²( 60° )
= × 0.25
we substitute
= 0.375 × 0.25
= 0.09375
∴ / × 100 = 0.09375 × 100
⇒ 9.38%
Therefore, the percentage of light that gets through this combination is 9.38
Answer: Temperature T = 218.399K.
Explanation:
Q= 129W/m2
σ = 5.67 EXP -8W/m2K4
Q= σ x t^4
t = (Q/σ)^0.25
t= 218.399k