Answer:
the maximum height h to which the the water steam could rise is 40.65m
Explanation:
Given;
= 20m,
= 2atm ≈ 20265 N/m
Density of water ρ = 1000 kg/
Note: we take point 1 at the free surface of the water in the tank and point 2 at the top of the water trajectory. we also take reference level at the bottom of the tank.
fluid velocity at the free surface of tank is very low (
≅ 0) and at the top of the water trajectory 
= 0
Step 1: Applying Bernoulli equation between poin 1 and point 2
/ρg + 
/2g + = 
/ρg + 
/2g + 
/ρg + = 
/ρg +
= ( - )/ρg +
Substituting values into we have,
= 
Answer:
A) 5 MPa , 55 MPa
B) maximum stress = 55 MPa, maximum shear stress = 25 MPa
Explanation:
using the given Data
free surface of a solid body
α
= 50 MPa, α
= 10 MPa , t
= -15 MPa
attached below is the detailed solution to the question
1 liter = .264 gallon
1 km = .621 mile
this means that 58.3km/L is equal to 137.13mpg
so
500/137.13 = 3.65 gallons of gas
3.65 x 3.5 = $12.78
Answer:
The description including its scope is presented throughout the section below.
Explanation:
- Such operation must be carried out in compliance with all statutes, legislation, building standards, guidelines, and rules relating to that same task, not all of which are restricted to either the U.S Disability Act, the Ecological laws as well as the workplace Safety Act as modified.
- This same consultant shall appoint and could be completely liable for almost all processes and sequences just for conducting the Job.
Answer:
The stress in the rod is 39.11 psi.
Explanation:
The stress due to a pulling force is obtained dividing the pulling force by the the area of the cross section of the rod. The respective area for a cylinder is:
Replacing the diameter the area results:
Therefore the the stress results:
