Answer : Option A) Atomic number of Arsenic is 33.
Explanation : Arsenic contains same number of protons in its atomic nucleus. In arsenic there are 33 protons found in the atomic nucleus. Hence, the atomic number will be 33. It has 5 valence electrons in its outermost shell, which is also called as valence shell. So, its valency becomes 5.
Answer:
3.47 ×10^-10
Explanation:
The equation of the reaction is 2Cr3+(aq) + Pb(s)------->2Cr2+(aq) + Pb2+(aq)
A total of two moles of electrons were transferred in the process. The chromium was reduced while the lead was oxidized. Hence the lead species will constitute the oxidation half equation and the chromium will constitute the reduction half equation.
E°cell = E°cathode - E°anode
E°cathode = -0.41 V
E°anode = -0.13 V
E°cell = -0.41 -(-0.13) = -0.28 V
From
E°cell = 0.0592/n log K
n= 2, K= the unknown
-0.28 = 0.0592/2 log K
log K = -0.28/0.0296
log K = -9.4595
K = Antilog ( -9.4595)
K= 3.47 ×10^-10
The volume of your 0.25 m stock solution that is needed to make 200 ml of 0.010 m NaCl is <u>0.008 L</u>
Concentration is the abundance of a constituent divided by way of the overall volume of an aggregate. several sorts of mathematical descriptions may be outstanding: mass concentration, molar concentration, variety concentration, and extent awareness.
Calculation:-
C₁ = 0.25 M
V₁ = ?
C₂ = 0.010 M
V₂ = 200 ml = 0.2 L
V₁ = C₂V₂/C₁
= 0.010 × 0.2 / 0.25
=<u> 0.008 L</u>
The concentration of a substance is the quantity of solute found in a given amount of solution. Concentrations are normally expressed in terms of molarity, defined because of the variety of moles of solute in 1 L of answer.
The Concentration of an answer is a measure of the quantity of solute that has been dissolved in a given amount of solvent or answer. A concentrated answer is one that has a rather huge quantity of dissolved solute.
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Answer:
option A = C₂H₄ + 3O₂ → 2CO₂ + 2H₂O
Explanation:
Law of conservation of mass:
This law stated that mass can not be created or destroyed in chemical reaction. It just changed from one to another form.
For example:
C₂H₄ + 3O₂ → 2CO₂ + 2H₂O
28 g + 96 g = 88 g + 36 g
124 g = 124 g
This reaction correctly hold the law of conservation of mass.
Other options:
C + 4H₂ → CH₄
12 g + 8g = 16 g
20 g = 16 g
This reaction do not hold the law of conservation of mass.
3H₂O → 3H₂ + 3O₂
54 g = 6 g + 96 g
54 g = 102 g
This reaction do not hold the law of conservation of mass.
2Na + Cl → NaCl
46 g + 35.5 g = 58.5 g
81.5 g = 58.5 g
This reaction do not hold the law of conservation of mass.
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