To determine the solubility of ammonium chloride, we first find the curve for ammonium chloride in the chart for solubility measured in grams of solute per 100 mL of water solvent. Reading the chart at 60 degrees Celsius, approximately 55 grams of ammonium chloride will dissolve in 100 mL of water. Therefore, the solubility of ammonium chloride is 55 grams NH4Cl/100mL H2O at 60°C.
Smashing a cake the ingredients didn't change but it's appearance did
According to the periodic table, carbon's molar mass is 12.011 grams per mole (that's the small number under the element). So, just multiply like this to get the answer:
So, there are approximately 0.208 grams in 2.5 moles of carbon.
This problem is providing two reduction-oxidation (redox) reactions in which the oxidized and reduced species can be identified by firstly setting the oxidation number of each element:
Reaction 1: 2K⁺I⁻ + H₂⁺O₂⁻ ⇒2K⁺O⁻²H⁺ + I₂⁰
Reaction 2: Cl₂⁰ + H₂⁰ ⇒ 2H⁺CI⁻
Next, we can see that iodine is being oxidized and oxygen reduced in reaction #1 and chlorine is being reduced and hydrogen oxidized in reaction #2 because the oxidized species increase the oxidation number whereas the reduced ones decrease it.
In such a way, the correct choice is C.
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