Answer:
the normality of the given solution is 0.0755 N
Explanation:
The computation of the normality of the given solution is shown below:
Here we have to realize the two sodiums ions per carbonate ion i.e.
N = 0.321g Na_2CO_3 × (1mol ÷ 105.99g)×(2eq ÷ 1mol)
= 0.1886eq ÷ 0.2500L
= 0.0755 N
Hence, the normality of the given solution is 0.0755 N
Answer:
5.995 psi
Explanation:
30 psi = 2.04 atm
75 mL = 0.075 L
15 mL = 0.015 L
0.075 L/ 2.04 atm = 0.015 L/x
0.075x = 0.0306
x = 0.408
0.408 atm = 5.995 psi
I assume this is a true or false question. I would say true