Answer:
The Emf of the given cell at [Fe2+] = 2.0 M and [Fe3+] = 1.9 M is 0.48 V
Explanation:
The half cell reaction can be written as :
Anode-Half (oxidation) :
......E = 0.77 V
(multiply this equation by 4 to balance the electrons)
Cathode-half (reduction)
....E= 1.23 V
According to Nernst Equation
n = number of electron transferred in the cell reaction = 4
The balanced equation is :
Insert the value of log Q in Nernst Equation:
(using :
)
What is [H+] given that the measured cell potential is -0.464 V and the anode reduction ... What half-reaction occurs at the cathode during the electrolysis of molten ... PbO2(s) + 4H+(aq) + SO42-(aq) + 2e- → PbSO4(s) + 2H2O(l); E° = 1.69 V .... For the cell Cu(s)|Cu2+||Ag+|Ag(s), the standard cell potential is 0.46 V. A cell ... hopw this helps
It releases all types of pollution into the air, as well as potentially endangering birds and other wildlife that live near that forest.
hope that helps!
I´m pretty sure its magnesium iron silicate.
Heat comes from the release of energy, like a campfire. The reactants, such as the wood in the campfire, have a certain amount of energy stored in their chemical bonds. This energy can be released when these materials react with the oxygen in the air (combustion) and are converted to the combustion products (usually carbon dioxide and water). Chemists use a quantity called the heat of formation as a measure of the energy stored in these compounds. The energy change associated with a combustion reaction is the difference between the energy (heat of formation) of the products and the energy (heat of formation) of the reactants.
hope this helped