All categories

3 years ago

Specify whether CF4 is polar. Match the correct word in the left column to the blanks in the sentence on the right.

Chemistry

1 answer:

zavuch27 [327]3 years ago

5 0

Answer:

CF4 is non polar

polar, no net, nonpolar

Explanation:

The overall polarity of a molecule depends on the presence of polar bonds within the molecule and the orientation of the polar bonds to produce an overall dipole moment. This implies that the presence of polar bonds in a molecule does not automatically imply that such molecule is polar or will display on overall dipole moment. The orientation of the individual dipoles affects the overall dipole moment of the molecule.

A polar molecule results from an unequal/unsymmetrical sharing of valence electrons. While there may be unequal sharing of electrons in the individual bonds, in a nonpolar molecule like CF4 these bonds are evenly distributed and cancel out. There is no net dipole and the CF4 is non-polar. Hence the order of words chosen in the answer to fill in the blanks.

You might be interested in

Reacting Solutions of Aluminum Chloride with Potassium Hydroxide

gizmo_the_mogwai [7]

1Al2(SO4)3 + 3ZnCl2 → 2AlCl3 + 3ZnSO4

The coefficients represents moles. There is 1 mole of Aluminum Sulfate, 3 moles of Zinc(II) Chloride, 2 moles of Aluminum Chloride, and 3 moles of Zinc(II) Sulfate.

Now add all the coefficients/moles.

9 is the sum of all the coefficients.

7 0

3 years ago

Read 2 more answers

Which of the chemical equations is balanced?

Simora [160]

The third equation is properly balanced.

To figure this out, set up tables to check if each element has the same amount on both sides. If you do this for the third equation, copper, hydrogen, oxygen, and nitrogen are all balanced,

The first equation is incorrect due to the fact Iron, Fe, is not balanced on both sides. This is shown by the subscripts given.

The second equation is incorrect as Sulfur is not properly balanced and neither is sodium.

The fourth equation is incorrect as Aluminum is not properly balanced. On the reactants side, Aluminum is 4 while on the products, Aluminum is 8.

Hope this helps!

6 0

3 years ago

)- symbols following elements silver, Copper ,magnesium ,sulphur

NNADVOKAT [17]

Ag,Cu,Mg,S are the answers...............

3 0

3 years ago

Read 2 more answers

If you had 240 L container at 479 k and 300 kpa, what would the volume be if you changed the conditions to STP

nydimaria [60]

Answer:

The answer to your question is V2 = 434.7 l

Explanation:

Data

Volume 1 = V1 = 240 l Volume 2 = ?

Temperature 1 = T1 = 479°K Temperature 2 = T2 = 293°K

Pressure 1 = P1 = 300 KPa Pressure 2 = P2 = 101.325 Kpa

Process

1.- Use the combined gas law to solve this problem

P1V1/T1 = P2V2/t2

-Solve for V2

V2 = P1V1T2 / T1P2

2.- Substitution

V2 = (300)(240)(293) / (479)(101.325)

3.- Simplification

V2 = 21096000 / 48534.675

4.- Result

V2 = 434.7 l

6 0

3 years ago

Given these reactions, where X represents a generic metal or metalloid 1 ) H 2 ( g ) + 1 2 O 2 ( g ) ⟶ H 2 O ( g ) Δ H 1 = − 241

anygoal [31]

Answer : The enthalpy of the given reaction will be, -1048.6 kJ

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

The main reaction is:

$XCl_4(s)+2H_2O(l)\rightarrow XO_2(s)+4HCl(g)$ $\Delta H=?$

The intermediate balanced chemical reactions are:

(1) $H_2(g)+\frac{1}{2}O_2(g)\rightarrow H_2O(g)$ $\Delta H_1=-241.8kJ$

(2) $X(s)+2Cl_2(g)\rightarrow XCl_4(s)$ $\Delta H_2=+461.9kJ$

(3) $\frac{1}{2}H_2(g)+\frac{1}{2}Cl_2(g)\rightarrow HCl(g)$ $\Delta H_3=-92.3kJ$

(4) $X(s)+O_2(g)\rightarrow XO_2(s)$ $\Delta H_4=-789.1kJ$

(5) $H_2O(g)\rightarrow H_2O(l)$ $\Delta H_5=-44.0kJ$

Now reversing reaction 2, multiplying reaction 3 by 4, reversing reaction 1 and multiplying by 2, reversing reaction 5 and multiplying by 2 and then adding all the equations, we get :

(1) $2H_2O(g)\rightarrow 2H_2(g)+O_2(g)$ $\Delta H_1=2\times 241.8kJ=483.6kJ$