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Tomtit [17]
2 years ago
11

A circular loop of radius r is rotated through a magnetic field B, which of the following would increase the magnetic flux throu

gh the loop by a factor of 16?
Doubling B and quadrupling r.
Quadrupling B and doubling r.
B remains constant and quadrupling r.
Doubling B and doubling r.
Physics
1 answer:
s344n2d4d5 [400]2 years ago
3 0

Answer: B

Explanation: I think

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The sprinter ran 110 m in 11 seconds. What was her average speed in m/s?
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Answer:

10 m/s

Explanation:

110/11=10

5 0
2 years ago
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Gravity is the force that keeps us on the Earth. It pulls us towards the center of the Earth. If you were to move from the surfa
Nikitich [7]
<h2>Answer: B. Gravitational potential energy </h2>

Explanation:

<em>The gravitational potential energy is the energy that a body or object possesses, due to its position in a gravitational field. </em>

That is why this energy depends on the relative height of an object with respect to some point of reference and associated with the gravitational force.

In the case of the <u>Earth</u>, in which  <u>the gravitational field is considered constant</u>, the value of the gravitational potential energy U_{p} will be:

U_{p}=mgh  

Where m is the mass of the object, g the acceleration due gravity and h the height of the object.

As we can see, the value of U_{p} is directly proportional to the height.

6 0
3 years ago
Electrons are accelerated in the picture tube of a television through potential difference of 8.00 * 10 ^ 3 V. (Use the values q
maria [59]

Answer:

\lambda=1.37\times 10^{-11}\ m

Explanation:

Give that,

The potential difference of the electrons, V=8\times 10^{3}\ V

We need to find the wavelength of the electrons.

Using the conservation of energy,

2meV=\dfrac{h^2}{\lambda^2}\\\\\lambda=\sqrt{\dfrac{h^2}{2meV}}

Put all the values,

\lambda=\sqrt{\dfrac{(6.63\times 10^{-34})^2}{2\times 9.1\times 10^{-31}\times 1.6\times 10^{-19}\times 8\times 10^3}}\\\\\lambda=1.37\times 10^{-11}\ m

So, the wavelength of the electrons is 1.37\times 10^{-11}\ m.

7 0
2 years ago
(a) what will an object weigh on the moon's surface if it weighs 100 n on earth's surface
juin [17]
We know the equation

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To work out the weight on the moon, we will need its mass, and the gravitational field strength of the moon.
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So using the information given about the earth weight, we can find the mass by substituting 100N for weight, and we know the gravity on earth is 10Nm*2 (Use the gravitational field strength provided by your school, I am assuming yours in 10Nm*2)

Therefore,

100N = mass × 10
mass= 100N/10
mass= 10 kg

Now, all we need are the moon's gravitational field strength and to apply this to the equation

weight = 10kg × (gravity on moon)
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Can you please stop pasting this question, just go to his profile and ask him.
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