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Radda [10]
3 years ago
15

PLEASEE HELPP ME WITH THIS QUESTIONN!!!!!1

Chemistry
1 answer:
MAXImum [283]3 years ago
7 0

Answer:

hi dont report me we are friends

Explanation:

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you wish to make a 0.161 m hydroiodic acid solution from a stock solution of 3.00 m hydroiodic acid. how much concentrated acid
mestny [16]

5.367 ml of the concentrated acid must be added to obtain a total volume of 100 ml of the dilute solution.

Dilution is defined as the process in which the concentration of a sample is decreased by adding more solvent. The dilution formula is given below.

C₁V₁ = C₂V₂

where C₁ = initial concentration of sample = 3.00 m

V₁ = initial volume of sample

C₂ = final concentration after dilution = 0.161 m

V₂ = total final volume after dilution = 100 ml

Plug in the values to the formula and solve for the volume of the concentrated acid that must be added.

C₁V₁ = C₂V₂

3.00 m (V₁) = 0.161 m (100 ml)

V₁ = 5.367 ml

Learn more about dilution here: brainly.com/question/1615979

#SPJ4

3 0
1 year ago
In beta decay, what is emitted?
Bingel [31]
I'm pretty sure its an electron. I hope this helps! (:
5 0
3 years ago
Read 2 more answers
Telluric acid (H2TeH4O6) is a diprotic acid with Ka1 = 2.0x10-8 and Ka2 = 1.0x10-11. A 0.25 M H2TeH4O6 contains enough HCl so th
tensa zangetsu [6.8K]

Answer:

5x10⁻⁶ = [HTeH₄O₆⁺]

Explanation:

The first dissociation equilibrium of the telluric acid in water is:

H₂TeH₄O₆ + H₂O ⇄ HTeH₄O₆⁺ + H₃O⁺

Using H-H equation for telluric acid:

<em>pH = pKa + log₁₀ [HTeH₄O₆⁺] / [H₂TeH₄O₆]</em>

pKa of telluric acid is -logKa1

pKa = -log 2.0x10⁻⁸

pKa = 7.699

As concentration of [H₂TeH₄O₆] is 0.25M, replacing in H-H equation:

3.00 = 7.699+ log₁₀ [HTeH₄O₆⁺] / [0.25M]

-4.699 = log₁₀ [HTeH₄O₆⁺] / [0.25M]

2x10⁻⁵ = [HTeH₄O₆⁺] / [0.25M]

<h3>5x10⁻⁶ = [HTeH₄O₆⁺]</h3>

7 0
2 years ago
Why is the inner core's state of matter different from the outer core's state of matter
Ganezh [65]
Because the inner course is a totally different thing then the outer course
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3 years ago
Through 100 ml of a one-molar sodium hydroxide solution, 896 ml (n.a.) of carbon dioxide was passed gas. Determine the mass solu
Semmy [17]
Through 100 ml of a one-molar sodium hydroxide solution, 896 ml (n.a.) of carbon dioxide was passed gas. Determine the mass solution of salt in the resulting solution. Density of a one-molar alkali solution, take equal to 1.04 g / ml.
5 0
2 years ago
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