Answer:
The horizontal distance traveled by the projectile is 15.23 m.
Explanation:
Given;
angle of projection, θ = 25⁰
initial velocity of the projectile, u = 15 m/s
time of flight, t = 1.12 s
The the travelling path of the object is calculated as the range of the projectile
Therefore, the horizontal distance traveled by the projectile is 15.23 m.
<span>Volume of air in the balloon 1.01 x 10^6 L
Density of air is 1.20 g/l
Mass = Density X Volume
So mass of the air in the Balloon= ( 1.01 x 10^6) X 1.20 = 1.212 x 10^6 g
As the air is heated, the volume of air in the balloon expands to 1.10x 10^6 L
Density= Mass/ voume
So the Density of heated air = 1.212 x 10^6/ 1.10x 10^6 = 1.101 g/l
The answer is 1.101 g/l.</span>
Answer:x=23.4 cm
Explanation:
Given
mass of block 
inclination 
coefficient of static friction 
coefficient of kinetic friction 
distance traveled 
spring constant 
work done by gravity+work done by friction=Energy stored in Spring
True
False
True
My answers
