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Kamila [148]
3 years ago
12

CNA Secondary and Preparatory School

Physics
1 answer:
ale4655 [162]3 years ago
3 0

Answer:

2:13 2) cm' c6462.

Explanation:

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The parcel will undergo projectile motion, which means that it will have motion in both the horizontal and vertical direction.


First, we determine how long the parcel will fall using:


s = ut + 1/2 at²


where s will be the height, u is the initial vertical velocity of the parcel (0), t is the time of fall and a is the acceleration due to gravity.


5.5 = (0)(t) + 1/2 (9.81)(t)²

t = 1.06 seconds



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Consider a parachutist that has reached terminal velocity. which of the following is true? A.) The acceleration of the parachuti
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The correct answer is:
<span>B.) At terminal velocity there is no net force 

In fact, when the parachutist reaches the terminal velocity, his velocity does not change any more. It means that the acceleration acting on the parachutist is zero, and for Newton's second law, this means the net force acting on him is zero:
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3 years ago
An archer shoots an arrow at a 75.0 m distant target; the bull’s-eye of the target is at same height as the release height of th
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Answer:

the shooting angle ia 18.4º

Explanation:

For resolution of this exercise we use projectile launch expressions, let's see the scope

      R = Vo² sin (2θ) / g

      sin 2θ = g R / Vo²

      sin 2θ = 9.8 75/35²

      2θ = sin⁻¹ (0.6)

      θ = 18.4º

To know how for the arrow the tree branch we calculate the height of the arrow at this point

       X2 = 75/2 = 37.5 m

We calculate the time to reach this point since the speed is constant on the X axis

       X = Vox t

       t2 = X2 / Vox = X2 / (Vo cosθ)

        t2 = 37.5 / (35 cos 18.4)

        t2 = 1.13 s

With this time we calculate the height at this point

        Y = Voy t - ½ g t²

        Y = 35 sin 18.4   1.13 - ½ 9.8 1,13²

        Y = 6.23 m

With the height of the branch is 3.5 m and the arrow passes to 6.23, it passes over the branch

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3 years ago
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Can someone help me with this Physics question please?
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Answer:

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