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Kamila [148]
3 years ago
12

CNA Secondary and Preparatory School

Physics
1 answer:
ale4655 [162]3 years ago
3 0

Answer:

2:13 2) cm' c6462.

Explanation:

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2 is the answer hope you have a great day
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A car that experiences no frictional force is started and caused to move. For the car to continue in that motion, the gas pedal
astraxan [27]

Explanation:

Gas pedal is not required to used on friction less surface. On a friction less surface once the car is started and caused to move, car continues to move with same velocity as there is no opposing force. Therefore, no pressing of gas pedal required. However, this situation is not possible in real life, as friction is always present.

8 0
3 years ago
To get up on the roof, a person (mass 70.0kg) places a 6.00-m aluminum ladder (mass 10.0 kg) against the house on a concrete pad
Julli [10]

The magnitude of the forces acting at the top are;

\mathbf{F_{Top, \ x}} = 132.95 N

\mathbf{F_{Top, \ y}} = 0

The magnitude of the forces acting at the bottom are;

\mathbf{F_{Bottom, \ x}} = \mathbf{ F_f} = -132.95 N

\mathbf{F_{Bottom, \ y}} = 784.8 N

The known parameters in the question are;

The mass of the person, m₁ = 70.0 kg

The length of the ladder, l = 6.00 m

The mass of the ladder, m₂ = 10.0 kg

The distance of the base of the ladder from the house, d = 2.00 m

The point on the roof the ladder rests = A frictionless plastic rain gutter

The location of the center of mass of the ladder, C.M. = 2 m from the bottom of the ladder

The location of the point the person is standing = 3 meters from the bottom

g = The acceleration due to gravity ≈ 9.81 m/s²

The required parameters are;

The magnitudes of the forces on the ladder at the top and bottom

The strategy to be used;

Find the angle of inclination of the ladder, θ

At equilibrium, the sum of the moments about a point is zero

The angle of inclination of the ladder, θ = arccos(2/6) ≈ 70.53 °C

Taking moment about the point of contact of the ladder with the ground, <em>B </em>gives;

\sum M_B = 0

Therefore;

\sum M_{BCW} = \sum M_{BCCW}

Where;

\sum M_{BCW} = The sum of clockwise moments about <em>B</em>

\sum M_{BCCW} = The sum of counterclockwise moments about <em>B</em>

Therefore, we have;

\sum M_{BCW} = 2  × (2/6) × 10.0 × 9.81 + 3.0 × (2/6) × 70 × 9.81

\sum M_{BCCW} = F_R × √(6² - 2²)

Therefore, we get;

2  × (2/6) × 10.0 × 9.81 + 3.0 × (2/6) × 70 × 9.81  = F_R × √(6² - 2²)

F_R  = (2  × (2/6) × 10.0 × 9.81 + 3.0 × (2/6) × 70 × 9.81)/(√(6² - 2²)) ≈ 132.95

The reaction force on the wall, F_R ≈ 132.95 N

We note that the magnitude of the reaction force at the roof, F_R = The magnitude of the frictional force of bottom of the ladder on the floor, F_f but opposite in direction

Therefore;

F_R = -F_f

F_f = - F_R ≈ -132.95 N

Similarly, at equilibrium, we have;

∑Fₓ = \sum F_y = 0

The vertical component of the forces acting on the ladder are, (taking forces acting upward as positive;

\sum F_y = -70.0 × 9.81 - 10 × 9.81 + F_{By}

∴ The upward force acting at the bottom, F_{By} = 784.8 N

Therefore;

The magnitudes of the forces at the ladder top and bottom are;

At the top;

\mathbf{F_{Top, \ x}} = F_R ≈ 132.95 N←

\mathbf{F_{Top, \ y}} = 0 (The surface upon which the ladder rest at the top is frictionless)

At the bottom;

\mathbf{F_{Bottom, \ x}} = F_f ≈ -132.95 N →

\mathbf{F_{Bottom, \ y}} = F_{By} = 784.8 N ↑

Learn more about equilibrium of forces here;

brainly.com/question/16051313

8 0
3 years ago
A monkey climbs vertically on a vine. It’s motion is shown on the following graph of vertical position y vs time t.
Andrew [12]

Answer:

0 m/s

Explanation:

if you look at the graph you will see that where the number 5 is there is a straight line meaning there is no motion.

no movement = no speed or distance, and without anything to calculate your answer has to be zero

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True or false? A tide with the least distance between low and high tides is called a neap tide.
aksik [14]

The answer is True. Neap tides are when there is the least distance between low and high tides.

6 0
3 years ago
Read 2 more answers
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