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julsineya [31]
3 years ago
8

What is the effect on the period of a pendulum if you decrease its length by 6.35%? (Answer this question in terms of the initia

l period T.) T' = 0.87703 Incorrect: Your answer is incorrect. T
Physics
1 answer:
konstantin123 [22]3 years ago
5 0

Answer:

T' = 0.9677T

Explanation:

The period of a pendulum is given by the following formula:

T=2\pi \sqrt{\frac{l}{g}}

l: length of the pendulum

g: gravitational acceleration

If the length of the pendulum is decreased in 6.35% the length of the pendulum becomes:

l'=l-0.0635l=0.9365l

The new period for a length of l' is:

T'=2\pi \sqrt{\frac{l'}{g}}=2\pi \sqrt{\frac{0.9365l}{g}}=\sqrt{0.9365}(2\pi \sqrt{\frac{l}{g}})=0.9677(2\pi \sqrt{\frac{l}{g}})\\\\T'=0.9677T

hence, the new period is 0.9677T

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4 years ago
A Micro –Hydro turbine generator rotor is accelerating uniformly from an angular velocity of 610 rpm to its operating angular ve
solniwko [45]

Answer:

The rotor's angular velocity is 82.73rad/s

Explanation:

It is a curvilinear movement of a constant radius. If there is uniform angular acceleration, then it is a circular motion with constant acceleration, whose equations are analogous to that of the translational motion.

Calculating the initial velocity of the rotor, V1 in rad/s

V1 = 610rev/minute × 6.28 × 1miute/60secs

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Using kinematic equation to calculate the final velocity of the rotor

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Angular acceleration = 5.9rad/s^2

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V2 = V1 + a × t

V2 = 63.85 + (5.9)× (3.2)

V2 = 63.85 + 18.88

V2 = 82.73rads/s

4 0
3 years ago
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How much money did congress authorize to be spent on its construction
ser-zykov [4K]

Answer:

20,000

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4 years ago
A tennis ball hits with an initial velocity of 25 m/s [10 o above the
Sav [38]

First, calculate the components of its initial velocity v0:

v0x = v0cos10 = 24.6 m/s

v0y = v0sin10 = 4.34 m/s

The ball reaches its peak when vy = 0. Let's calculate the time it takes for vy to become zero:

vy = v0y - gt ---> t = v0y/g = 0.44 s

The horizontal distance it travels in this time is

x = v0xt = (24.6 m/s)(0.44 s)

= 10.8 m

Note that the net is 15 m away. After traveling a horizontal distance of 10.8 m, the height of the ball is

y = -(1/2)gt^2 + v0yt + 2.1

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= -0.95 m + 1.9 m + 2.1 m

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Note that this is the height of the ball at its peak. While the ball is well above the net at its peak, it is well short of its required horizontal distance to clear it. Instead, let's find the time it takes for the tennis ball to travel a horizontal distance of 15 m first:

x = v0xt ----> t = x/v0x = (15 m)/(24.6 m/s) = 0.61 s

Then calculate the height y when t = 0.61 s. If y > 0.9 m (height of the net), then the ball will clear the net.

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3 0
3 years ago
A mass is attached to the end of a spring and set into oscillation on a horizontal frictionless surface by releasing it from a c
Aneli [31]

Answer

given,

x = (3.9 cm)sin[(9.3 rad/s)πt]

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now on comparing

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sin[(9.3 rad/s)πt] = 0.667

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3 years ago
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