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serg [7]
3 years ago
10

Air at 200 kpa and 800k enters an adiabatic nozzle at low velocity (can be considered negligible) and is discharged at a pressur

e of 90 kpa. if the isentropic efficiency of the nozzle is 90%, determine: [20]
a. the exit temperature if the process is isentropic
b. the maximum possible exit velocity
c. the actual exit temperature
d. the actual exit velocity
Physics
1 answer:
scZoUnD [109]3 years ago
7 0

the answer is c. the actual exit temperature


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A motor produces less mechanical energy than the energy it uses because the motor?
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<span>A motor produces less mechanical energy than the energy it uses because the motor looses some energy to heat.</span>
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A sphere of volume 1.20×10−3m3 hangs from a cable. When the sphere is completely submerged in water, the tension in the cable is
KATRIN_1 [288]

Answer:

B = 62.9 N

Explanation:

This is an exercise on Archimedes' principle, where the thrust force equals the weight of the  liquid

         B = ρ g V

write the equilibrium equation

         T + B -W = 0

         B = W- T               (1)

use the density to write the weight

         ρ = m / V

        m = ρ V

         W = ρ g V

substitute in  1

         B = m g -T

         B = \rho_{body} g V - T

To finish the calculation, the density of the material must be known, suppose it is steel  \rho_{body} = 7850 kg / m³

calculate

         B = 7850 9.8 1.20 10⁻³ - 29.4

          B = 92.3 - 29.4

          B = 62.9 N

4 0
2 years ago
PLS HELP!!! WILL GIVE BRAINLIEST
grandymaker [24]

Answer:

did you ever get the answer

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2 years ago
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Energy is defined as
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I believe that your answer is going to be C. The ability to do work
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3 years ago
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Please do number 25! Explain how you got your answer with detail to get Brainliest! Thank you!
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John weighs 200 pounds.
In order to lift himself up to a higher place, he has to exert force of 200 lbs.

The stairs to the balcony are 20-ft high.
In order to lift himself to the balcony, John has to do
(20 ft) x (200 pounds)  =  4,000 foot-pounds of work.

If he does it in 6.2 seconds, his RATE of doing work is
(4,000 foot-pounds) / (6.2 seconds)  =  645.2 foot-pounds per second.

The rate of doing work is called "power".

(If we were working in the metric system (with SI units),
the force would be in "newtons", the distance would be in "meters",
1 newton-meter of work would be 1 "joule" of work, and
1 joule of work per second would be 1 "watt".
Too bad we're not working with metric units.)

So back to our problem.

John has to do 4,000 foot-pounds of work to lift himself up to the balcony,
and he's able to do it at the rate of 645.2 foot-pounds per second.

Well, 550 foot-pounds per second is called 1 "horsepower".

So as John runs up the steps to the balcony, he's doing the work
at the rate of

           (645.2 foot-pounds/second) / (550 ft-lbs/sec per HP)

=  1.173 Horsepower.  GO JOHN !

(I'll betcha he needs a shower after he does THAT 3 times.)
_______________________________________________

Oh my gosh !  Look at #26 !  There are the metric units I was talking about.

Do you need #26 ?

I'll give you the answers, but I won't go through the explanation,
because I'm doing all this for only 5 points.

a).  5
b).  750 Joules
c).  800 Joules
d).  93.75%

You're welcome.

And #27 is 0.667 m/s .
7 0
2 years ago
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