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ANEK [815]
3 years ago
15

A source outputs data at the rate of 1,000,000 bits/sec. The transmitter uses binary PAM with raised cosine pulse shaping. If th

e ideal baseband channel has a cutoff frequency of 850 kHz, what is the maximum roll-off factor that can be applied to the pulse shaping?
Engineering
1 answer:
musickatia [10]3 years ago
7 0

Answer:

maximum roll-off factor is 0.7

Explanation:

given data

rate of output data  = 1,000,000 bits/sec

cutoff frequency fc = 850 kHz

solution

we know bandwidth frequency is same as that of bandwidth

we apply here fc formula that is

fc = ω ( 1 + α )     ..........1

here

ω = data rate ÷ 2   .............2

ω = 1000  ÷ 2  

ω = 500000 Hz

so put now value in eq 1

fc = ω ( 1 + α )

850000= 500000  ( 1 + α )

solve it we get

α = 0.7

so, maximum roll-off factor is 0.7

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The settlement of foundations is typically the result of three separate occurrences that take place in the soil which provides s
evablogger [386]

Answer:

The differences are listed below

Explanation:

The differences between consolidation and compaction are as follows:

In compaction the mechanical pressure is used to compress the soil. In consolidation, there is an application of stead pressure.

In compaction, there is a dynamic load by rapid mechanical methods like tamping, rolling, etc. In consolidation, there is static and sustained pressure applied for a long time.

In compaction, the soil volume is reduced by removing air from the void. In consolidation, the soil volume is reduced by squeezing out water from the pores.

Compaction is used for sandy soil, consolidation on the other hand, is used for clay soil.

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3 years ago
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Which of the following is the last step in creating a budget?
Greeley [361]

Answer:

<em>D. Determine saving or debt</em>

Explanation:

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3 years ago
Which of the following would not be considered hot work? A chipping B soldering C
tankabanditka [31]
I believe the answer is D: brazing
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5 0
3 years ago
How high a building could fire hoses effectively spray from the ground? Fire hose pressures are around 1 MPa. (It is also said t
Mrac [35]

Answer:

z_{2} = 91.640\,m

Explanation:

The phenomenon can be modelled after the Bernoulli's Principle, in which the sum of heads related to pressure and kinetic energy on ground level is equal to the head related to gravity.

\frac{P_{1}}{\rho\cdot g} + \frac{v_{1}^{2}}{2\cdot g}= z_{2}+\frac{P_{2}}{\rho\cdot g}

The velocity of water delivered by the fire hose is:

v_{1} = \frac{(300\,\frac{gal}{min} )\cdot(\frac{3.785\times 10^{-3}\,m^{3}}{1\,gal} )\cdot(\frac{1\,min}{60\,s} )}{\frac{\pi}{4}\cdot (0.3\,m)^{2}}

v_{1} = 0.267\,\frac{m}{s}

The maximum height is cleared in the Bernoulli's equation:

z_{2}= \frac{P_{1}-P_{2}}{\rho\cdot g} + \frac{v_{1}^{2}}{2\cdot g}

z_{2}= \frac{1\times 10^{6}\,Pa-101.325\times 10^{3}\,Pa}{(1000\,\frac{kg}{m^{3}} )\cdot(9.807\,\frac{m}{s^{2}} )} + \frac{(0.267\,\frac{m}{s} )^{2}}{2\cdot (9.807\,\frac{m}{s^{2}} )}

z_{2} = 91.640\,m

7 0
3 years ago
During Atterberg limit tests in the soil mechanics laboratory, the students obtained the following results from a clayey soil. L
m_a_m_a [10]

<u>the liquid limit</u>

LL=-0.8078x*49.503

LL=-0.8078(25)+49.503

LL=29.308

<u>plasticity index of the soil</u>

PL=217.2%+17.8%/2

PL=17.5

PI=LL-PL

PI=29.308-17.5

PL=11.808

Hope this helps, now you know the answer and how to do it. HAVE A BLESSED AND WONDERFUL DAY! As well as a great rest of Black History Month! :-)  

- Cutiepatutie ☺❀❤

6 0
4 years ago
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