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cupoosta [38]
3 years ago
5

PLZ HELP WILL MARK BRAINLYIST!!!!

Chemistry
1 answer:
Whitepunk [10]3 years ago
6 0

Answer:

Hey mate down is your answer

Explanation:

Specific heat is an intensive property like

(density , color, etc.....)

that does not depend on the amount of a substance present

This allows substances to be identified

using their specific heat

<em><u>MAR</u></em><em><u>K</u></em><em><u> </u></em><em><u>MY</u></em><em><u> </u></em><em><u>ANSW</u></em><em><u>ER</u></em><em><u> </u></em><em><u>AS</u></em><em><u> </u></em><em><u>BRANLIST</u></em><em><u> ANSWER</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

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Convert 1.500 L to cm3. To the correct number of significant figures.
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Answer:

1500 cubic centimeters or cm^3

Explanation:

1 liter is 1000 cm^3

move the decimal 3 places to right

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Calculate ΔGrxn for this equation, rounding your answer to the nearest whole number. CaCO3(s) → CaO(s) + CO2(g) ΔGf,CaCO3 = −1,1
FrozenT [24]

Answer: \Delta G_{rxn} for the given reaction is 130.19kJ/mol

Explanation:

To Calculate the \Delta G_{rxn}, we use the formula:

\Delta G_{rxn}=\Delta G_{products}-\Delta G_{reactants}

For the given chemical reaction:

CaCO_3(s)\rightarrow CaO(s)+CO_2(g)

We are given:

\Delta G_{CaCO_3}=-1128.76kJ/mol\\\Delta G_{CaO}=-604.17kJ/mol\\\Delta G_{CO_2}=-394.4kJ/mol

Now, to calculate \Delta G_{rxn}, we put the values in the above equation:

\Delta G_{rxn}=(\Delta G_{CaO}+\Delta G_{CO_2})-\Delta G_{CaCO_3}

\Delta G_{reaction}=(-604.17-394.4)-(-1128.76)kJ/mol\\\Delta G_{reaction}=130.19kJ/mol

As, the value of \Delta G_{reaction} comes out to be positive, the reaction is said to be non-spontaneous reaction.

3 0
3 years ago
If an object has a volume of 5 mL and a mass of 50 g, what is the density of the object?
mr Goodwill [35]
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What are the resonance structures of the<br>carbonate (CO32-) ion?​
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