Answer : The value and unit of the rate constant for this reaction is, 
and 
respectively.
Explanation :
As we know that half-life of zero-order and second-order reaction depend on the concentration of reactant while the half-life of first-order reaction is independent of the concentration of the reactant.
The expression of half-life for zero order reaction:
![t_{1/2}=\frac{[A_o]}{2k}](https://tex.z-dn.net/?f=t_%7B1%2F2%7D%3D%5Cfrac%7B%5BA_o%5D%7D%7B2k%7D)
The expression of half-life for first order reaction:
The expression of half-life for second order reaction:
![t_{1/2}=\frac{1}{[A_o]k}](https://tex.z-dn.net/?f=t_%7B1%2F2%7D%3D%5Cfrac%7B1%7D%7B%5BA_o%5Dk%7D)
The given reaction can not be first order reaction because it is independent of the concentration of the reactant.
So, the given reaction can be zero order or second order.
First we have to calculate the value of rate constants for zero order.
and,
From this we conclude that the reaction can not be zero order.
Now we have to calculate the value of rate constants for second order.
and,
From this we conclude that the reaction is a second order.
Therefore, the value and unit of the rate constant for this reaction is, and respectively.
It has 8 valence electrons because the charge is -2.
Answer:
45.9m
Explanation:
Given parameters:
Mass of the ball = 1kg
Initial velocity = 30m/s
Unknown:
Height the ball will travel = ?
Solution:
At the maximum height, the final velocity of the ball will be 0;
Using ;
V² = U² - 2gh
V is the final velocity
U is the initial velocity
g is the acceleration due to gravity
h is the height
0² = 30² - (2 x 9.8 x h)
0 = 900 - 19.6h
h = 45.9m
An empirical formula is the "reduced" version of a molecular formula. For example, CH3 is the empirical formula for C2H6, C3H9, C4H12, and so forth. The difference in subscripts between an empirical formula and molecular formula is given by the constant n. If n is a whole number, this means the numerator is the molecular formula. So the answer is D. <span>subscript of C in molecular formula = n  subscript of C in empirical formula. This can be rewritten as:
n = subscript of C in molecular formula/subscript of C in empirical formula</span>
The answer is D. easier, higher
