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UkoKoshka [18]
3 years ago
10

PLZ HELP MEEEEEEE,;-;

Physics
1 answer:
laiz [17]3 years ago
7 0

Answer:

thxs for the points

Explanation:

because just started

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In comparing sunspots to other areas of the sun's surface one can say that sunspots are...?
taurus [48]

Answer:

D. Cooler

Explanation:

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The amount of steering wheel movement needed to turn will ____________ the faster you go.
Naddika [18.5K]

Answer:

The answer to your question is Decrease

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3 years ago
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A planet’s gravity is related to which of the following? (Points : 5)
katovenus [111]

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3 years ago
7.22 Ignoring reflection at the air–water boundary, if the amplitude of a 1 GHz incident wave in air is 20 V/m at the water surf
Serga [27]

Answer:

z = 0.8 (approx)

Explanation:

given,

Amplitude of 1 GHz incident wave in air = 20 V/m

Water has,

μr = 1

at 1 GHz, r = 80 and σ = 1 S/m.

depth of water when amplitude is down to  1 μV/m

Intrinsic impedance of air = 120 π  Ω

Intrinsic impedance of  water = \dfrac{120\pi}{\epsilon_r}

Using equation to solve the problem

  E(z) = E_0 e^{-\alpha\ z}

E(z) is the amplitude under water at z depth

E_o is the amplitude of wave on the surface of water

z is the depth under water

\alpha = \dfrac{\sigma}{2}\sqrt{\dfrac{(120\pi)^2}{\Epsilon_r}}

\alpha = \dfrac{1}{2}\sqrt{\dfrac{(120\pi)^2}{80}}

\alpha =21.07\ Np/m

now ,

  1 \times 10^{-6} = 20 e^{-21.07\times z}

  e^{21.07\times z}= 20\times 10^{6}

taking ln both side

21.07 x z = 16.81

z = 0.797

z = 0.8 (approx)

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4 years ago
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lozanna [386]

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2 years ago
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