What is a height gage?

The explosion of a hydrogen bomb can be approximated by a fireball with a temperature of 7200 K, according to a report published

Iteru [2.4K]

Answer:

a

The rate of radiation of the energy is $E_r = 1.523747635*10^9 W/m^2$

b

The irradiation is $G =46.177\ kW/m^2$

c

The amount of energy absorbed is $E_B = 461.772 KJ$

d

The oak Tree would catch fire because the temperature of the blast(7200 K) is higher than the flammability limit (650 K) of the oak tree and secondly the thickness is very small

Explanation:

From the question we are told that

The temperature is $T = 7200K$

The diameter of the ball is $d = 1.5 km = 1.5 *1000 = 1500m$

Hence the radius = $= \frac{1500}{2} = 750m$

The total energy radiated can be mathematically represented as

$E = \sigma A T^4$

Where $\sigma$ is the Stefan-Boltzmann constant $\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = 5.67*10^{-8} W \ \cdot m^{-2} K^{-4}$

A is the area of a sphere = $\pi d^2 = 3.142 * 1500^2 = 7.069500 *10 ^6\ m^2$

Substituting values we have

$E = 5,67*10^{-8} * 7.069500*10^6 * 7200^4$

$=1.077*10^{15} W$

Now the state of the energy is mathematically represented as

$Rate \ of \ energy \ radiation (E_r)= \frac{E}{A} = \sigma T^4$

$= 5.67*10^{-8} * 7200^2$

$= 1.523747635*10^9 W/m^2$

A sketch illustrating the b part of the question is shown on the first uploaded image

looking at the height at which the blast occurs(16km) as compared to the height of the wall we notice that the height of the wall is negligibly small

from the diagram x can be calculated as follows

$x = \sqrt{40^2 + 16^2}$

$= 43.0813 Km$

This value of x represents the radius of the blast(assuming it is spherical ) when it is at that wall

Now the irradiation G is mathematically represented as

$G = \frac{E}{4 \pi r^2}$

Here r = 43.0813 Km = 43.0813 × 1000 = 43081.3 m

$G= \frac{1.077*10^15}{4 \pi (431081.3^2)}$

$G =46.177\ kW/m^2$

Generally the amount of energy absorbed can be mathematically represented as

$Amount \ of \ energy \ absorbed \ (E_B ) = G * t$

Where t is the time taken

Therefore $E_B = 46.177 *10 = 461.77 KJ$

6 0

3 years ago

tech a says that small vacuum leaks can be found with a vacuum gauge. tech b says that the catalytic converter is typically loca

schepotkina [342]

Both are true. Tech A claims that a vacuum gauge can be used to locate tiny vacuum leaks. According to tech B, the catalytic converter is usually placed behind the muffler.

<h3>Which of the following links the catalytic converter to the exhaust manifold?</h3>

Tailpipe. The catalytic converter has cleaned up the exhaust gases, which are then sent out of the car and into the atmosphere via the tailpipe, the last link in the exhaust system.

<h3>Which of the following exhaust system parts aids in lowering exhaust emissions?</h3>

Hazardous pollutants from engine exhaust are decreased by the catalytic converter. The converter, which is situated between the exhaust manifold and the muffler, works with heat and metals that serve as catalysts.

To know more about vacuum gauge visit:-

brainly.com/question/20989381

#SPJ4

8 0

1 year ago

2. It is a measuring instrument used to record the amount of

lyudmila [28]

Answer:

The correct option is;

D. Electric meter

Explanation:

An electric meter is a metering device that is used for the measurement of the electric power consumption of an electrical powered tools, a living space or a building

Electric meter readings are used by electric utility company to sell electric power to consumers at a given rate such that it allows the electric utility company to receive payment for the total power supplied, and for the consumer to regulate the amount of power consumed

The electric meters are usually calibrated in kilowatt hour (kWh) and prepaid meter displays the amount of units of power bought, while post paid meters are usually read once each billing period which is usually one month.

3 0

3 years ago

Given the following MATLAB statement: ( 3 + 2 ) / 5 * 4 + 5 ^ 2 In what order will these operations be done?

Andrei [34K]

Answer:

first is the parentheses, (3+2)=5 next is the exponent 5^2=25, next is the division 5 / 5 = 1, then the multiplication 4*1=4 and then you add 4+25=29. so the answer is 29.

7 0

3 years ago

A very specific part of the population is called a

V125BC [204]

A specific part of the population is a subgroup.

6 0

3 years ago