Answer:
4. A series of steps engineers use to solve problems.
Explanation:
The process of engineering design is a sequence of procedures that engineers pursue to arrive at a solution to a specific problem. Most times the solution includes creating a product such as a computer code, which fulfills certain conditions or performs a function. If the project in-hand includes designing, constructing, and testing it, then engineers probably adopt the design process. Steps of the process include defining the problem, doing background research, specifying requirements, brainstorming solutions, etc.
Answer:
a). Work transfer = 527.2 kJ
b). Heat Transfer = 197.7 kJ
Explanation:
Given:
= 5 Mpa
= 1623°C
= 1896 K
= 0.05 ![m^{3}](https://tex.z-dn.net/?f=m%5E%7B3%7D)
Also given ![\frac{V_{2}}{V_{1}} = 20](https://tex.z-dn.net/?f=%5Cfrac%7BV_%7B2%7D%7D%7BV_%7B1%7D%7D%20%3D%2020)
Therefore,
= 1 ![m^{3}](https://tex.z-dn.net/?f=m%5E%7B3%7D)
R = 0.27 kJ / kg-K
= 0.8 kJ / kg-K
Also given : ![P_{1}V_{1}^{1.25}=C](https://tex.z-dn.net/?f=P_%7B1%7DV_%7B1%7D%5E%7B1.25%7D%3DC)
Therefore,
= ![P_{2}V_{2}^{1.25}](https://tex.z-dn.net/?f=P_%7B2%7DV_%7B2%7D%5E%7B1.25%7D)
![5\times 0.05^{1.25}=P_{2}\times 1^{1.25}](https://tex.z-dn.net/?f=5%5Ctimes%200.05%5E%7B1.25%7D%3DP_%7B2%7D%5Ctimes%201%5E%7B1.25%7D)
= 0.1182 MPa
a). Work transfer, δW = ![\frac{P_{1}V_{1}-P_{2}V_{2}}{n-1}](https://tex.z-dn.net/?f=%5Cfrac%7BP_%7B1%7DV_%7B1%7D-P_%7B2%7DV_%7B2%7D%7D%7Bn-1%7D)
![\left [\frac{5\times 0.05-0.1182\times 1}{1.25-1} \right ]\times 10^{6}](https://tex.z-dn.net/?f=%5Cleft%20%5B%5Cfrac%7B5%5Ctimes%200.05-0.1182%5Ctimes%201%7D%7B1.25-1%7D%20%20%5Cright%20%5D%5Ctimes%2010%5E%7B6%7D)
= 527200 J
= 527.200 kJ
b). From 1st law of thermodynamics,
Heat transfer, δQ = ΔU+δW
= ![\frac{mR(T_{2}-T_{1})}{\gamma -1}+ \frac{P_{1}V_{1}-P_{2}V_{2}}{n-1}](https://tex.z-dn.net/?f=%5Cfrac%7BmR%28T_%7B2%7D-T_%7B1%7D%29%7D%7B%5Cgamma%20-1%7D%2B%20%5Cfrac%7BP_%7B1%7DV_%7B1%7D-P_%7B2%7DV_%7B2%7D%7D%7Bn-1%7D)
=![\left [ \frac{\gamma -n}{\gamma -1} \right ]\times \delta W](https://tex.z-dn.net/?f=%5Cleft%20%5B%20%5Cfrac%7B%5Cgamma%20-n%7D%7B%5Cgamma%20-1%7D%20%5Cright%20%5D%5Ctimes%20%5Cdelta%20W)
=![\left [ \frac{1.4 -1.25}{1.4 -1} \right ]\times 527.200](https://tex.z-dn.net/?f=%5Cleft%20%5B%20%5Cfrac%7B1.4%20-1.25%7D%7B1.4%20-1%7D%20%5Cright%20%5D%5Ctimes%20527.200)
= 197.7 kJ
The mechanical energy of an object is a combination of its potential energy and its <em><u>kinetic</u></em><em><u> </u></em><em><u>energy</u></em><em><u>.</u></em>
Answer:
The difference in weight and size?
Explanation:
It explains itself :P