Inert gas does not affect the equilibrium position:
It is because the partial pressures of the reaction components remain the same.
What is Inert Gas?
- Under a given set of conditions, an inert gas is a gas that does not undergo chemical reactions.
- The noble gases (helium, neon, argon, krypton, xenon, and radon) were previously known as "inert gases" due to their perceived lack of involvement in any biochemical processes.
- Because inert gases are non-reactive, they do not affect equilibrium partial pressures and thus do not affect volume.
- An inert gas does not react with the reactants or products; it does not change the concentration of the products and reactants. Furthermore, because the volume is constant, the concentrations are unaffected. As a result, this does not affect equilibrium.
The equilibrium position won't change if an inert gas is added. A volume change won't change the equilibrium position if the total moles of gas in the products and reactants are the same. When the volume is reduced, the process changes to create fewer moles of gas.
Learn more about the inert gas here,
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Answer:
solvents dissolve in liquids
I found the attached image with the same statement of your question and think it may be very useful for you that I use it to show how to answer this question (furthermore I think it may be the same reaction that you forgot to include).
As you can see, there are one image on the left side and other image on hte right side of the figure.
Those images contains drawings that represent molecules and a legend that permit you to distinguish the kind of atoms in each molecule.
Using that, you can indicate the chemical reaction as the transformation of the molecules on the left side onto the molecules on the right side:
Left side:
3 molecules of CH4 and 3 molecules of N2Cl4
Right side:
3 molecules of CCl4, 3 molecules of N2 and 6 molecules of H2
That is represented as:
3CH4 + 3 N2Cl4 -----> 3 CCl4 + 3N2 + 6H2And that is the balanced chemical equation for the reaction shown in the figured attached.I hope this is useful for you..
Let the 8% solution be A, the 20% solution be B and the final solution be C.
C = A + B
C = 12 + B
0.16C = 0.08(12) + 0.2(B)
0.16(12 + B) = 0.96 + 0.2B
0.96 = 0.04B
B = 24 Liters
C = 12 + 24
C = 36 Liters
Answer:
120g
Explanation:
Based on the reaction, when 1 mole of propane and 5 moles of oxygen react, 3 moles of CO2 and 4 moles of H2O are produced. The ratio of production is 3 moles of CO2 per 4 moles of H2O.
Thus, we need to convert mass of water to moles using its molar mass:
Moles H2O (Molar mass: 18g/mol):
63g H2O * (1mol / 18g) = 3.5 moles H2O
Converting to moles of CO2:
3.5 moles H2O * (3 moles CO2 / 4 moles H2O) = 2.625 moles CO2
Mass CO2 (Molar mass: 44g/mol):
2.625 moles CO2 * (44g / mol) = 115.5g of CO2 are released
<h3>120g
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