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wel
3 years ago
8

Ethanol undergoes combustion in oxygen to produce carbon dioxide gas and liquid water. The standard heat of combustion of ethano

l, c2h5oh(l), is -1366.8 JK/mol. Given that [co2(g)] = -393.5kg/mol and [h20(l) = -285.8 KJ/ mol, what is the standard enthalpy of formation of ethanol?
Chemistry
1 answer:
Mama L [17]3 years ago
5 0

Answer:

-277.6\ \text{kJ/mol}

Explanation:

Heat of combustion of C_2H_5OH(l) = -1366.8 kJ/mol

Heat of formation of CO_2(g) = -393.5 kJ/mol

Heat of formation of H_2O(l) = -285.8 kJ/mol

The reaction is

C_2H_5OH(l)\rightarrow 2CO_2(g)+3H_2O(l)

Assuming x is the standard enthalpy of formation of ethanol

-1366.8=2\times (-393.5)+3\times (-285.8)-x\\\Rightarrow x=2\times (-393.5)+3\times (-285.8)+1366.8\\\Rightarrow x=-277.6\ \text{kJ/mol}

The standard enthalpy of formation of ethanol is -277.6\ \text{kJ/mol}.

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