The amount of work (W) done on an object is equal to the force (F) needed to lift

Physics

1 answer:

densk [106]2 years ago

3 0

Answer:

Work done during lifting up body is 0

Explanation:

From the question it is given that

Distance traveled by body during lifting is 2 m

since work done by body is given by

work done W = F x s x cosθ

Where F= mg = weight of body

s= distance traveled = 2m

θ = angle between force and distance vector

here θ = 90° as body is lifting up

on substituting the respected values we get

⇒ W = mg x 2 x cos90° = 0 {∵ cos90°= 0 }

Thus, work done during lifting up body is 0

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