Answer:B because all of the atoms exploded AND GRAVITY WAS CREATED AND forced molecules together (God caused it btw)
Explanation:The BIBLE
Answer:
independant=variable that has changed
dependant=variable affected by the change
water=independant, because if you put too much water the dependant that depends on water could die or too little dependant can die (dependant=plants)
Explanation:
Answer:
Explanation:
Well ik its not math for this but for the first one if u add
22+22+13+1 u get 58
then second one 1+22+22+2=47
1+22+22+24+1=70
1+22+22+13+1=59
U notice how that most or some are all going up to 50 except the third one
So that means its 1s22s22p24s1
Answer:
2 chlorine atoms.
Explanation:
H₂ + Cl₂ → 2HCl
The Law of Conservation of Mass states that matter can neither be created nor destroyed in a chemical reaction.
If 2 molecules of Hydrogen and 2 molecules of Chlorine is present in the reactants, the same no. of atoms should also be present in the product.
∴ the no. of chlorine atoms in the product is 2.
Answer: The standard enthalpy change for this reaction is -116 kJ
Explanation:
According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.
According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.
The given chemical reaction is,
![2H_2CO(g)\rightarrow 2C(s, graphite)+2H_2(g)+O_2(g)](https://tex.z-dn.net/?f=2H_2CO%28g%29%5Crightarrow%202C%28s%2C%20graphite%29%2B2H_2%28g%29%2BO_2%28g%29)
![\Delta H^0=232KJ](https://tex.z-dn.net/?f=%5CDelta%20H%5E0%3D232KJ)
Now we have to determine the value of
for the following reaction i.e,
![\Delta H^0'=?](https://tex.z-dn.net/?f=%5CDelta%20H%5E0%27%3D%3F)
According to the Hess’s law, if we reverse the reaction then the
will change its sign and if we half the reaction, then the
So, the value
for the reaction will be:
![\Delta H^0'=\frac{(-232kJ/mole)}{2}=-116kJ](https://tex.z-dn.net/?f=%5CDelta%20H%5E0%27%3D%5Cfrac%7B%28-232kJ%2Fmole%29%7D%7B2%7D%3D-116kJ)
Hence, the standard enthalpy change for this reaction is -116 kJ