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Burka [1]
3 years ago
7

A sheet of 8.5 inch by 11inch paper has a mass of 4.50 grams one square centimeter , 1cm2 of that sheet of paper will have a mas

s closets to ____grams (hint use 1inch = 2.54 centimeters and area = length times
A) 7.3
B)0.73
C) 0.073
D) 0.0073
Physics
1 answer:
finlep [7]3 years ago
3 0
The answer is option D.

Area of sheet, A1  = length × breadth
                       =  (8.5 inch * 2.54 cm) ×11 inch * 2.54 cm) 
                       = 603.22cm^{2}

Now, Mass of sheet, M1 = 4.50 gms

Thus, Area of sheet A2, = 1cm^{2}
And, Mass of sheet, M2 = ?

Thus,  Mass of M2 = \frac{4.50 gms}{603.22}
                                = 0.0073
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A piano string having a mass per unit length of 5.00 g/m is under a tension of 1350 N. Determine the speed of transverse waves i
padilas [110]

Answer:

The speed of transverse waves in this string is 519.61 m/s.

Explanation:

Given that,

Mass per unit length = 5.00 g/m

Tension = 1350 N

We need to calculate the speed of transverse waves in this string

Using formula of speed of the transverse waves

v=\sqrt{\dfrac{T}{\mu}}

Where, \mu = mass per unit length

T = tension

Put the value into the formula

v = \sqrt{\dfrac{1350}{5.00\times10^{-3}}}

v =519.61\ m/s

Hence, The speed of transverse waves in this string is 519.61 m/s.

6 0
3 years ago
Calculate the current through a 3.0 ω resistor with a voltage of 9.0 v across it.
gulaghasi [49]

Answer: 3 A

Explanation:

According to<u> Ohm's law</u>:  

V=R.I

Where:

V=9 V is the voltage

R=3\Omega is the resistance of the resistor

I is the electric current (the value we want to find)

Isolating I:

I=\frac{V}{R}

I=\frac{9 V}{3\Omega}

Finally:

I=3 A

7 0
3 years ago
A 100 kg astronaut weighs 980N on Earth. The same astronaut weighs only 162.2 N on the Moon. Which of the following statements e
andrey2020 [161]

Answer:

100

Explanation:

6 0
2 years ago
When the speed of the bottle is 2 m/s, the KE is kg m2/s2. When the speed of the bottle is 3 m/s, the KE is kg m2/s2. When the s
d1i1m1o1n [39]

mass of the bottle in each case is M = 0.250 kg

now as per given speeds we can use the formula of kinetic energy to find it

1) when speed is 2 m/s

kinetic energy is given as

K = \frac{1}{2}mv^2

K = \frac{1}{2}(0.250)(2)^2 = 0.5 J

2) when speed is 3 m/s

kinetic energy is given as

K = \frac{1}{2}mv^2

K = \frac{1}{2}(0.250)(3)^2 = 1.125 J

3) when speed is 4 m/s

kinetic energy is given as

K = \frac{1}{2}mv^2

K = \frac{1}{2}(0.250)(4)^2 = 2 J

4) when speed is 5 m/s

kinetic energy is given as

K = \frac{1}{2}mv^2

K = \frac{1}{2}(0.250)(5)^2 = 3.125 J

5) when speed is 6 m/s

kinetic energy is given as

K = \frac{1}{2}mv^2

K = \frac{1}{2}(0.250)(6)^2 = 4.5 J

3 0
3 years ago
Read 2 more answers
The speed of light in a vacuum is approximately 2.99 × 108 m/s, and the speed of light through a piece of glass is approximately
exis [7]

Option (b) is correct.The index of refraction for the glass is 1.52

Explanation:

velocity of light in vacuum= C= 2.99 x 10⁸m/s

Velocity of light in glass = V= 1.97 x 10⁸m/s

The refractive index is given by n=\frac{c}{v}

n= 2.99 x 10⁸/1.97 x 10⁸m/s

n= 1.52

Thus the refractive index of glass is 1.52

6 0
3 years ago
Read 2 more answers
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