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MrMuchimi
2 years ago
14

PLEASE HELP! IM TRYNA GET A GOOD GRADE! I ONLY HAVE 6 MINS LEFFTT

Chemistry
1 answer:
Arte-miy333 [17]2 years ago
6 0

Answer:

<h2><em><u>answer</u></em><em><u> </u></em><em><u>-</u></em><em><u> </u></em><em><u>b</u></em><em><u> </u></em><em><u>molarity </u></em></h2>

Explanation:

<h2><em><u>pl</u></em><em><u>ease</u></em><em><u> like</u></em><em><u> me</u></em></h2><h2><em><u>I </u></em><em><u>hope</u></em><em><u> answer</u></em><em><u> correct</u></em></h2>
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HURRRYYY <br> in a chemical reaction you will always have an excess reactant. true or false?
just olya [345]

Answer:

It's False

Explanation:

In a chemical reaction, reactants that are not used up when the reaction is finished are called excess reagents. The reagent that is completely used up or reacted is called the limiting reagent, because its quantity limits the amount of products formed.

Hope this helps you

8 0
3 years ago
Read 2 more answers
How many atoms are in a sample of chromium with a mass of 31 grams? O a 2.4 x 1024 atoms of chromium b 3.6 x 1023 atoms of chrom
lukranit [14]

Answer:

b. 3.66x10²³ atoms of chromium.

Explanation:

First we calculate how many moles are there in 31 grams of chromium, using its molar mass:

  • Molar Mass of Chromium = 51 g/mol (This can be found on any periodic table)
  • 31 g ÷ 51 g/mol =  0.608 mol

Then we <u>calculate how many atoms are there in 0.608 moles</u>, using <em>Avogadro's number</em>:

  • 0.608 mol * 6.023x10²³ atoms/mol = 3.66x10²³ atoms

The correct answer is thus option b. 3.66x10²³ atoms of chromium.

4 0
2 years ago
A sample of 0.200 moles of nitrogen occupies 0.400 L. Under the same conditions, what number of moles occupies 1.200 L
IRISSAK [1]

The number of mole of nitrogen that occupies 1.2 L under the same condition is 0.6 mole

<h3>Data obtained from the question </h3>
  • Initial mole (n₁) = 0.2 mole
  • Initial volume (V₁) = 0.4 L
  • Final volume (V₂) = 1.2 L
  • Final mole (n₂) =?

<h3>How to determine the final mole </h3>

The final mole can be obtained by using the ideal gas equation as illustrated below:

PV = nRT

Divide both side n

PV / n = RT

Divide both side by P

V / n = RT / P

RT / P = constant

V / n = constant

Thus,

V₁ / n₁ = V₂ / n₂

0.4 / 0.2 = 1.2 / n₂

2 = 1.2 / n₂

Cross multiply

2 × n₂ = 1.2

Divide both side by 2

n₂ = 1.2 / 2

n₂ = 0.6 mole

Learn more about ideal gas equation:

brainly.com/question/4147359

#SPJ1

7 0
2 years ago
What sample is a pure substance?A. a test tube of zinc oxide.
Mice21 [21]
The correct answer is A. A test tube of zinc oxide. Zinc oxide is a compound which is a pure substance composed of two or more elements. They can only be separated or broken down into its individual elements or smaller compounds by chemical means. Therefore, the answer is a test tube of zinc oxide.
7 0
3 years ago
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Help please??????????????????????
wolverine [178]

Answer:

this app is it tool for people to learn and grow not a place for people to place their homework and have it answered within. a few seconds

6 0
3 years ago
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