Answer:
less than
Explanation:
Given;
mass of the person, m = 100 kg
acceleration due to gravity, g = 9.8 m/s²
The reading on the scale is determined by applying Newton's second law of motion;
R = mg - ma
R = m(g-a)
at constant velocity, the acceleration is zero
a = 0
R = m(g-0)
R = mg
R = 100 x 9.8
R = 980 N
Thus, the scale reading is equal to the weight of the person but less than 1000 N
Answer:
(a) t = 1.1 x 10^-7 s
(b) 5.56 mm
(c) vx = 4.5 x 10^5 m/s, vy = 10^5 m/s
Explanation:
v = 4.5 x 10^5 m/s along horizontal direction
E = 9.60 x 10^3 N/C along vertical direction
(a) Let t be the time taken.
Horizontal distance, x = 5 cm = 0.05 m
Horizontal distance = horizontal velocity x time
0.05 = 4.5 x 10^5 x t
t = 1.1 x 10^-7 s
(b) Let the vertical displacement is y.
y = 1/2 a t^2
Here a be the acceleration.
a = force/ mass = q E / m = (1.6 x 10^-19 x 9.6 x 10^3) / (1.67 x 10^-27)
a = 9.19 x 10^11 m/s^2
So, y = 0.5 x 9.19 x 10^11 x (1.1 x 10^-7)^2 = 5.56 x 10^-3 m = 5.56 mm
(c) Let vx be horizontal component of velocity and vy be the vertical component of velocity after it travels for 5 cm horizontally.
vx is same as v because the acceleration in horizontal direction is zero.
vy = 0 + a t = 9.19 x 10^11 x 1.1 x 10^-7 = 10.109 x 10^4 m/s
vy = 1 x 10^5 m/s
Answer:
Find answer below.
Explanation:
a. Group 2: alkaline earth metals. Some examples of alkaline earth metals are magnesium, calcium, barium, etc.
b. Transition metals: metals with unpredictable properties.
c. Chlorine: halogen.
d. Metalloid: make good semiconductors.
e. Group 1: alkali metals. These includes the soft, light and reactive chemical elements found in group 1 of the periodic table. Some examples are hydrogen, potassium, lithium, sodium, etc.
f. Noble gases: has a full outer energy level (shell). These are chemical elements with eight valence electrons and as such have a full octet. Some examples are argon, neon, etc.
h. Metal: loses electron in bonding. They usually lose electrons in order to attain a full outer energy level or noble gas electronic configuration.
The formula for Kinetic Energy is:
KE = 1/2mv^2
So, KE = 1/2(500)(10)^2
KE = 1/2(500)(100)
KE = 1/2(50000)
KE = 25,000 J