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SCORPION-xisa [38]
3 years ago
10

1. A 20.0 kg weight is hanging from a rope. What is the force of tension on the rope?

Physics
1 answer:
Len [333]3 years ago
7 0

Explanation:

The tension on an object is equal to the mass of the object x gravitational force plus/minus the mass x acceleration. Tension Formula Questions: 1) There is a 5 kg mass hanging from a rope.

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A stone is dropped from a bridge and hits the pavement below in two seconds. What is the velocity of the stone when it hits the
Helen [10]
We have: a = v/t
Here, t = 2 s  [ Given ]
a = 9.8 m/s²  [constant value for earth system ]

Substitute their values into the expression:
9.8 = v/2
v = 9.8 × 2
v = 19.6 m/s

In short, Your Answer would be Option B

Hope this helps!
4 0
3 years ago
Read 2 more answers
Choose all of the examples of balanced forces.
SVEN [57.7K]

Answer:

book on flat table

Explanation: the table pushes upward on the book while gravity pulls downward.

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The presence of foreign pottery in a well-dated Egyptian context shows that this type of pottery cannot be more recent than thos
Nutka1998 [239]

Answer:

TERMINUS ANTE QUEM

Explanation: Terminus ante quem is an Archeological an a Latin term used to describe the date before which an event or events took place,it is also used to show the date before which Archeological works have been deposited in a given area.

Example, a pottery dating to the 4th century AD found on a surface would give that pottery with a terminus ante quem of the 4thcentury AD.

This type of cross dating can either be TERMINUS ANTE QUEM OR TERMINUS POST QUEM.

3 0
3 years ago
A block slides along a frictionless surface and onto a slab with a rough surface. The slab has mass of 4 kg and the block has ma
maxonik [38]

Answer: the friction force on the small block at t equals 1 second is 2N

Explanation:

Given the data in the question;

from the slope in the graph provided, we will get the acceleration of the slab

At t = 1 seconds

Slope = acceleration = ( 1 - 0) / ( 2 - 0 ) = 1/2 = 0.5 m/s²

Force = ma = 4 × 0.5 = 2 N

so by Newton's third law

Force on block will be same which is 2N

Therefore the friction force on the small block at t equals 1 second is 2N

3 0
3 years ago
A uniform, spherical, 1900.0 kg shell has a radius of 5.00 m. Find the gravitational force this shell exerts on a 1.80 kg point
Mandarinka [93]

Answer:

F=9.09\times 10^{-9} N

Explanation:

We are given that

Mass of spherical shell,m_1=1900 kg

Mass=m_2=1.80 kg

Radius of shell=r=5 m

Distance between two masses=r=5.01 m

Because distance measure from center .

Gravitational force

F=G\frac{m_1m_2}{r^2}

G=6.67\times 10^{-11} Nm^2/kg^2

Using the formula

F=6.67\times 10^{-11}\times \frac{1900\times 1.80}{(5.01)^2}

F=9.09\times 10^{-9} N

Hence,the gravitational force =F=9.09\times 10^{-9} N

6 0
3 years ago
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