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stich3 [128]
3 years ago
9

A child and sled with a combined mass of 48.8 kg slide down a frictionless hill that is 7.05 m high. If the sled starts from res

t, what is its speed at the bottom of the hill?
___m/s
Physics
1 answer:
nexus9112 [7]3 years ago
7 0

Answer:

Speed at bottom of the hill (v) = 11.74 m/s

Explanation:

Given:

Combined mass = 48.8 kg

Height h = 7.05 m

Find:

Speed at bottom of the hill (v)

Computation:

v² = 2gh

v = √2 x 9.8 x 7.05

v = √138.18

v = 11.74 m/s

Speed at bottom of the hill (v) = 11.74 m/s

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Which of the following statements is true about magnetic fields.
Marina CMI [18]

Answer:  

The earth's magnetic field protects the surface from strong electrical currents coming from the sun

Explanation:

The Earth's magnetic field called the “magnetosphere” – protects our atmosphere from the “solar wind.” That's the constant stream of charged particles flowing outward from the sun. When the magnetosphere shields the Earth from these solar particles, they get funneled toward the polar regions of our atmosphere.

The Earth's magnetic field serves to deflect most of the solar wind, whose charged particles would otherwise strip away the ozone layer that  protects  the Earth from harmful ultraviolet radiation. One stripping mechanism  is  for gas to be caught in bubbles of magnetic field, which are ripped off by solar winds.

8 0
3 years ago
A child with a weight of 430 N rides on a Ferris wheel, which has a radius of 17 m, and the linear velocity of the 3.5 m/s at an
Murrr4er [49]

At the lowest point on the Ferris wheel, there are two forces acting on the child: their weight of 430 N, and an upward centripetal/normal force with magnitude n; then the net force on the child is

∑ F = ma

n - 430 N = (430 N)/g • a

where m is the child's mass and a is their centripetal acceleration. The child has a linear speed of 3.5 m/s at any point along the path of the wheel whose radius is 17 m, so the centripetal acceleration is

a = (3.5 m/s)² / (17 m) ≈ 0.72 m/s²

and so

n = 430 N + (430 N)/g (0.72 m/s²) ≈ 460 N

6 0
2 years ago
on a very muddy football field, a 120 kg linebacker tackles an 75 kg halfback. immediately before the collision, the linebacker
Aleksandr-060686 [28]
B4 the tackle: 

<span>The linebacker's momentum = 115 x 8.5 = 977.5 kg m/s north </span>

<span>and the halfback's momentum = 89 x 6.7 = 596.3 kg m/s east </span>


<span>After the tackle they move together with a momentum equal to the vector sum of their separate momentums b4 the tackle </span>

<span>The vector triangle is right angled: </span>

<span>magnitude of final momentum = √(977.5² + 596.3²) = 1145.034 kg m/s </span>

<span>so (115 + 89)v(f) = 1145.034 ←←[b/c p = mv] </span>

<span>v(f) = 5.6 m/s (to 2 sig figs) </span>


<span>direction of v(f) is the same as the direction of the final momentum </span>

<span>so direction of v(f) = arctan (596.3 / 977.5) = N 31° E (to 2 sig figs) </span>


<span>so the velocity of the two players after the tackle is 5.6 m/s in the direction N 31° E </span>




<span>btw ... The direction can be given heaps of different ways ... N 31° E is probably the easiest way to express it when using the vector triangle to find it</span>
4 0
3 years ago
Which most likely indicates a chemical change has occurred?
Law Incorporation [45]

green liquid becoming a red liquid

4 0
2 years ago
Read 2 more answers
Explain how Pascal's principle can be used to design a fluid power system and describe how a fluid power system works.
zhenek [66]
Pascal's law of fluid transfer states that when there is an increase in fluid pressure, the rest of the extrinsic variables also increases. For example, in a flow of liquid in an orifice, there is a contraction of diameter in the orifice part. The fluid that will go in there increases in pressure and thereby an increase in velocity as well.
4 0
3 years ago
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