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2 years ago

WHICH SIGNAL IS TRANSFERRED IN ELECTRICAL WIRE ?

Physics

1 answer:

Dvinal [7]2 years ago

8 0

Answer:

electrical signal is transferred in electrical wire

Explanation:

electrical signals are transmitted between segments of the axon by successive opening of channels down the atonal membrane with negative and positive charge fluxing on either side of the membrane through selectively permeable chlorine , sodium or potassium channels.

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One thousand grams of seawater would consist of how many grams of dissolved substances? 65 635 35 965

Naya [18.7K]

<span>One thousand grams of seawater has 35 grams of dissolved substances ... on the average. While the salinity of the Earth's oceans and seas varies, the average salinity of seawater rests at 3.5%. Consider one liter or sea or ocean water. One liter has 1,000 milliliters (mL) in it. To find 3.5% of 1,000, we would multiply with the decimal place adjusted for percentages: 1000 x .035 = 35. Therefore, for every 1,000 mL of seawater, we will find 35 grams of (mostly) sodium chloride, otherwise known as salt.</span>

7 0

2 years ago

Read 2 more answers

f the absolute pressure in a tank is 128 kPa , determine the pressure head in mm of mercury. The atmospheric pressure is 100 kPa

White raven [17]

Answer:

211 mmHg

Explanation:

Absolute Pressure = Gauge Pressure + Atmospheric pressure

128 = Gauge Pressure + 100

Gauge Pressure = 28 KPa = 28 × 10³ Pa

Also Gauge Pressure = ρgh

ρ = density = 13550 kg/m³

g = acceleration due to gravity = 9.8 m/s²

h = pressure head = ?

28 × 10³ = 13550 × 9.8 × h

h = 28000/(13550 × 9.8)

h = 0.211 m = 211 mm

5 0

3 years ago

You are trying to decide between two new stereo amplifiers. One is rated at 130 W per channel and the other is rated at 200 W pe

NARA [144]

Answer:

The sound level will be 1.870 dB louder.

Explanation:

Given that,

Power = 130 W

Power = 200 W

We need to calculate the sound level

Using formula of sound level

$I_{dB}=10\log(\dfrac{I}{I_{0}})$

For one amplifier,

$I_{1}=10\log(\dfrac{130}{I_{0}})$ ...(I)

For other amplifier,

$I_{2}=10\log(\dfrac{200}{I_{0}})$ ...(II)

For difference in dB levels

$I_{2}-I_{1}=10\log(\dfrac{200}{I_{0}})-10\log(\dfrac{130}{I_{0}})$

$I_{2}-I_{1}=10\log(\dfrac{200}{I_{0}}\times\dfrac{I_{0}}{130})$

$I_{2}-I_{1}=10\log(\dfrac{200}{130})$

$I_{2}-I_{1}=1.870\ dB$

Hence, The sound level will be 1.870 dB louder.

7 0

3 years ago

The SI unit of power is the watt. Which of the following units are equivalent to the watt?

Llana [10]

Answer:

The right option is (A) V.A

Explanation:

Power: This is the rate at which work is done. Or it is the produce of force and velocity. The S.I unit of power is Watt (W). Other units include Horse power(hp), foot-pound per minutes, etc.

Generally, power can be represented as,

Power = Energy/time

P = W/t......................... Equation 1

Where p = power, w = Work or energy, t = time in seconds.

Electrical energy: This is the product of potential difference and the quantity of charge.

∴ W = VQ............................... Equation 2

Where V = potential difference, Q = quantity of charge and W = Energy or Work done.

Also Q = It........................ Equation 3.

where I = current in ampere, t = time in seconds

Substituting equation 3 into equation 3

W = VIt............................ Equation 4.

Also substituting Equation 4 into Equation 1

P = VIt/t = VI = voltage(V)×Current(A)

Therefore the equivalent unit of power is

P = V.A.

The right option is (A) V.A

3 0

3 years ago

In a science museum, a 110 kg brass pendulum bob swings at the end of a 13.9 m -long wire. the pendulum is started at exactly 8:

saw5 [17]

The number of oscillations completed by the pendulum is 2736.

The amplitude of the pendulum is 3.47 m.

The given motion is an underdamped motion. So its frequency will be similar to that of a simple harmonic motion.

The frequency of oscillation is defined as the number of oscillations completed in unit time. It is calculated using the formula.

f=(1/2π)*√(l/g)

where f is the frequency, l is the length of the pendulum, and g is the acceleration due to gravity.

Given the length of the wire l=13.9 m and acceleration due to gravity g=9.8 m/s^2. The frequency of oscillation is:

f=(1/(2*3.14)) * √(13.9/9.8)

f=0.19 Hz (approximately)

Since the pendulum started oscillating at 8:00 am, 4 hours has been passed when it shows 12:00 pm. So time t=4 hours or t=4*3600. Hence t=14400 s. The total number of oscillations is then given by the formula,

n=ft

where n is the number of oscillations.

n=0.19*14400=2736.

In damping motion, the amplitude of the pendulum decreases with time. The amplitude of the pendulum is given by the formula,

A' = A exp (-b*t)

where A' is the amplitude after time t, A is the initial amplitude, b is the damping constant, and t is the time.

Here A=1.2 m, b=0.010 kg/s and t=14400 s.

A' = 1.2 exp (-0.010*14400)

A'=3.47 m (approximately)

Learn more about amplitude.

brainly.com/question/21632362

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5 0

2 years ago