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Olenka [21]
2 years ago
15

What is the difference between professional and casual communication styles?

Physics
1 answer:
Lady bird [3.3K]2 years ago
7 0

Answer:

professional communication style is expected to be formal while the casual is informal.

Explanation:

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State any ten reasons why students in Uganda need to study physics.(use examples of the possible technological advancements whic
Trava [24]

Answer:

The answer is "physics ".

Explanation:

Physics is the branch of science that addresses the properties of crystalline and its interaction with the fundamental elements of the universe. It covers subjects ranging in quantum mechanics with extremely little ones with quantum mechanics to the whole cosmos. You must be constant whether you like it or not, thus everyone must learn physics, irrespective of whether they're in Uganda, and plenty of other countries should have physics to dare study.

8 0
3 years ago
Helpp
frosja888 [35]
B, refraction I believe.
5 0
2 years ago
Juan whose weight is 500 N is standing on the ground. The force the ground exerts on
Anna71 [15]

Answer:

more than 500 n i think the answer will

8 0
2 years ago
Read 2 more answers
single goose sounds a loud warning when an intruder enters the farmyard. Some distance from the goose, you measure the sound lev
Goryan [66]

Answer:

The sound level of the 26 geese is  Z_{26}= 96.15 dB

Explanation:

From the question we are told that

    The  sound level is Z_1 =  81.0 \ dB

     The number of geese is N = 26

Generally the intensity level of sound is mathematically represented as

        The intensity of sound level in dB  for one  goose is mathematically represented as

                       Z_1 = 10 log [\frac{I}{I_O} ]

Where I_o is the  threshold level of intensity with value  I_o = 1*10^{-12} \  W/m^2

            I is the intensity for one goose in W/m^2

For 26 geese the intensity would be  

          I_{26} = 26 * I

   Then  the intensity of 26 geese in dB is  

              Z_{26} = 10 log[\frac{26 I }{I_o} ]

               Z_{26} = 10 log (\ \ 26 *  [\frac{ I }{I_o} ]\ \ )

               Z_{26} = 10 log (\ \ 26  \ \ ) *   (\ \  10 log [\frac{ I }{I_o} ]\ \ )

 From the law of logarithm we have that

              Z_{26} = 10 log 26 +  10 log [\frac{I}{I_0} ]

                    = 14.15 + 82

                    Z_{26}= 96.15 dB

               

               

           

4 0
3 years ago
The brick wall (of thermal conductivity 1.12 W/m · ◦ C) of a building has dimensions of 2.8 m by 5 m and is 8 cm thick. How much
hichkok12 [17]

Answer:

Explanation:

If H be the heat flowing in time t through an area of A having thickness d

H = k A x ( θ₂ - θ₁ ) t / d  , k is thermal conductivity , ( θ₂ - θ₁ ) is temperature difference of walls

putting the given values

= (1.12 x 2.8x 5 x 9 x 16.7 x 60 x 60) / .08

= 1.06 x 10⁸ J .

5 0
2 years ago
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