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3 years ago

11

The car travels 52m in 21 seconds before it comes to a complete stop after the driver applies the brakes. What was the car's ini

tial speed?

1 answer:

prisoha [69]3 years ago

5 0

Answer:

2.48 m/s

Explanation:

D=vt

52 = V 21

V= 52/21=2.47m/s

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What material was the hindenburg made of?

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You carry a fire hose up a ladder to a height of 10 m above ground level and aim the nozzle at a burning roof that is 9 m high.

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Answer:

The value is $P_1 = 314645 \ Pa$

Explanation:

From the question we are told that

The height is $h_2 = 10 m$

The height of the burning roof is $k = 9 m$

The horizontal distance is $d = 7 \ m$

The height of the truck is $h_1 = 0.5 \ m$

Generally the time for the water to hit the roof from the hose is mathematically represented as

$t = \sqrt{\frac{2 * (h_2 - k)}{g} }$

=> $t = \sqrt{\frac{2 * (10 - 9)}{9.8} }$

=> $t = 0.4518 \ s$

Generally the velocity of the water is mathematically evaluated as

$v_2 = \frac{d}{t}$

$v_2 = \frac{ 7}{0.4518}$

$v_2 = 15.5 \ m/s$

Generally from Bernoulli's Equation we have that

$P_1 + \frac{1}{2} v_1^2 * \rho + \rho *g *h_1 = P_2 + \frac{1}{2} v_2^2 * \rho + \rho *g *h_2$

Here $P_1 [\tex] is pressure in the chamber which we are to calculate , [tex]P_2 [\tex] is the atmospheric pressure with value [tex]P_2 = 101325 \ Pa [\tex] , [tex]v_1 [\tex] is the velocity of the water before it starts flowing with value [tex]v_1 = 0 m/s [\tex] , [tex]\rho [\tex] is the density of water with value [tex]\rho = 1000 \ kg/m^3 [\tex] So [tex]P_1 + \frac{1}{2} 0^2 * 1000 + 1000 *9.81 *0.5 = 101325 + \frac{1}{2}* 15.5^2* 1000 + 1000 *9.81 *10$

$P_1 = 314645 \ Pa$

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abody starts from rest and accelerate uniformly at 8m/s/s.calculate the distance travelled by the body in 10s?

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Explanation:

using the formula: S=ut+½gt², where u=0, S=?, g=8m/s², t=10seconds.

S=ut+½gt² ("ut" term will cancel because u=0).

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