Question

For a reaction, Delta * H ^ 0 = - 75KJ / m * o * l and triangle S^ 0 =-0.081KJ/(K* mol) . At what temperatures is this reaction spontaneous?

Answer 1

Answer:

At temperatures below 924.93K.

Explanation:

Hello there!

In this case, according to the thermodynamic definition of the Gibbs free energy of reaction:

$\Delta G=\Delta H-T\Delta S$

Now, for us to determine the correct temperature range, we must make ΔG=0 and solve for T:

$T=\frac{\Delta H}{\Delta S} =\frac{-75kJ/mol}{-0.081kJ/mol-K}\\\\T=925.93K$

Thus at temperatures below 925.93 K we will have an spontaneous reaction (ΔG<0).

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