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2 years ago

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A mother is pulling a sled at constant velocity by means of a rope at 37°. The tension on the rope is 120 N. Mass of children pl

us sled is 55 kg. The mother has a mass of 61 kg. Find the static friction acting on the mother.

1 answer:

iren2701 [21]2 years ago

7 0

Answer:

f = 106.3 N

Explanation:

The force applied on the sled must be equal to the static frictional force to move the sled:

Tension Force Horizontal Component = Static Frictional Force

$TCos\theta = \mu W\\TCos\theta = \mu mg$

where,

T = Tension = 120 N

θ = angle of rope = 37°

μ = coefficient of static friction = ?

m = mass of children plus sled = 55 kg

g = acceleration due to gravity = 9.81 m/s²

Therefore,

$(120\ N)Cos\ 37^o = \mu (55\ kg)(9.81\ m/s^2)\\\\\mu = \frac{95.84\ N}{(55\ kg)(9.81\ m/s^2)}\\\\\mu = 0.18$

Now, the static friction acting on the mother will be:

$f = \mu mg = (0.18)(61\ kg)(9.81\ m/s^2)\\$

<u>f = 106.3 N</u>

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