The approximate acceleration of gravity for an object above the earth's surface is 9.8 m/s².
<h3>
Acceleration due to gravity </h3>
The acceleration due to gravity of an object above the Earth's surface is calculated from Newton's second law of motion and Newton's law of universal gravitation.
<h3>Force between the object and Earth</h3>
<h3>Weight of the object</h3>
Solve (1) and (2)
mg = GmM/R²
g = GM/R²
where;
- M is mass of Earth
- G is gravitational constant
- R is radius of the Earth = 6,371 km
g = (6.673 x 10⁻¹¹ x 5.98 x 10²⁴)/(6,371 x 10³)²
g = 9.8 m/s²
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Explanation:
C is correct.
Newton second law states that force is directly proportional to acceleration with m being the constant of variation.
So
A is wrong, the constant g only happens in free fall or in vertical direction
B and D are wrong due to the mathematical error or equation error
Answer: P = FV becuase all of them are equal in strength.
Explanation: In the straight forward cases where a constant force moves an object at constant velocity, the power is just P = Fv. In a more general case where the velocity is not in the same direction as the force, then the scalar product offorce and velocity must be used. P = Power, F = Force, V = Velocity.
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Explanation:
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Water goes through evaporation.
