Answer:
t = 6.68 seconds
Explanation:
The acceleration of the automobile, ![a=0.54\ m/s^2](https://tex.z-dn.net/?f=a%3D0.54%5C%20m%2Fs%5E2)
Initial speed of the automobile, u = 91 km/hr = 25.27 m/s
Final speed of the automobile, v = 104 km/hr = 28.88 m/s
Let t is the time taken to accelerate from u to v. It can be calculated as the following formula as :
![t=\dfrac{v-u}{a}](https://tex.z-dn.net/?f=t%3D%5Cdfrac%7Bv-u%7D%7Ba%7D)
![t=\dfrac{28.88-25.27}{0.54}](https://tex.z-dn.net/?f=t%3D%5Cdfrac%7B28.88-25.27%7D%7B0.54%7D)
t = 6.68 seconds
So, the time taken by the automobile to accelerate from u to v is 6.68 seconds. Hence, this is the required solution.
Answer:
I. Speed = 20m/s
II. Velocity = 20m/s due North.
Explanation:
<u>Given the following data;</u>
Distance = 40m
Time = 2secs
To find the speed;
Mathematically, speed is given by the formula;
![Speed = \frac{distance}{time}](https://tex.z-dn.net/?f=Speed%20%3D%20%5Cfrac%7Bdistance%7D%7Btime%7D)
Substituting into the equation, we have;
![Speed = \frac{40}{2}](https://tex.z-dn.net/?f=Speed%20%3D%20%5Cfrac%7B40%7D%7B2%7D)
<em>Speed = 20m/s.</em>
In physics, we use the same formula for calculating speed and velocity. The only difference is that speed is a scalar quantity and as such has magnitude but no direction while velocity is a vector quantity and as such it has both magnitude and direction.
![Velocity = \frac{distance}{time}](https://tex.z-dn.net/?f=Velocity%20%3D%20%5Cfrac%7Bdistance%7D%7Btime%7D)
<em>Therefore, the velocity is 20m/s due North</em>.
<span>You are given a QL = -26 μC charge that is placed on the x-axis at x = - 0.2 m and a QR = 26 μC charge that is placed at x = +0.2 m. The answers are:
The x-component of the electric field at x = 0 m and y = 0.2 m is 3.
The y-component of the electric field at x = 0 m and y = 0.2 m is 2.
</span>
The six steps of the scientific are:
1. State the question
2. Conduct research
3. Create a hypothesis
4. Perform the experiment
5. Analyze the data
6. Conclusion
So D. would be the correct answer, even though communicating the results could possibly be a step if it's required.