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Marysya12 [62]
3 years ago
5

NOBLE GASSES) Why’ are they Inert tho

Chemistry
2 answers:
Reptile [31]3 years ago
8 0

Answer:

i dont know?

Explanation:

why are they?!?!?!?!

igomit [66]3 years ago
5 0

Answer:

Why?  Because of electron shells.  Technically, they're not fully inert.  They have very low reactivity potential, and can only be forced to become reactive with difficulty.

Explanation:

All chemical reactivity is made possible through the atom's electron arrangement.  Electrons basically have shelves where they live, called "levels" or "shells".  Each level is farther from the nucleus than the previous one.  Atoms are most stable when their outer most shell (called the valence shell) is full.  Atoms with an incomplete shell will react with other atoms, in an attempt to either fill out the outer shell, or to rid itself of it's valence electrons so that that previous level becomes a full valence level.  If the valence shell ils already full, the atom will not be inclined to create compounds.

The first shell can hold up to two electrons.  After the first two electrons, any additional electrons have to begin a new shell.  The second shell can hold eight electrons before it becomes full.  Helium is the first noble gas on the periodic table, having two protons and two electrons.  Because helium's outer most shell is full, it does not react with other atoms.

By comparison, look at hydrogen and oxygen.  Oxygen has eight electrons.  The first two electrons occupy the first shell.  The remaining six go to the second shell.  This leaves the second shell with two empty spaces that can potentially be filled.  Meanwhile, hydrogen has one electron, with it's valence shell having an empty space for one additional electron.  Two hydrogen atoms give up their single electrons to an oxygen atom, so that all three end up with stable valence levels.

By the time an atom can fill out the second electron shell on it's own (10 total electrons) you end up with neon, the second noble gas.

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Refer to attachment please this is one of my study questions and im stuck
Reil [10]
Percentage yield= actual yield/theoretical yield x100
So you would have to do-
15/22 x 100. Hope this helps!!
3 0
2 years ago
A balloon is filled with 0.75 L of Helium gas at 35 °C. If the temperature is increased to 113 °C, what thewill new volume be?
faust18 [17]

Answer: 0.9398 Liters

Explanation:

Charles' Law

V1/ T1 = V2/T2

0.75/35 = ?/113

0.75/35 = 0.9398/113

4 0
3 years ago
the symbol for xenon (xe) would be a part of the noble gas notation for the element antimony. cesium.
trapecia [35]

The symbol for xenon (xe) would be a part of the noble gas notation for the element cesium.

For writing the electronic configuration of any element by using the preceding noble gas configuration, we simply use the symbols of noble gas belongs to the previous period of that particular elements. We can't use the symbol of noble gas of same period from which the element belong.

A is the wrong option because the noble gas in the preceding period to the period from which antimony belongs is krypton.

The actual electronic configuration of antimony is as follow:

[Kr] 4d10 5s2 5p3

B is correct option because the noble gas in the preceding period to the period from which Cesium belongs is Xenon.

The actual electronic configuration of Cesium is as follow:

[Xe] 6s1

Thus, we concluded that the symbol for xenon (xe) would be a part of the noble gas notation for the element cesium.

learn more about Noble gas:

brainly.com/question/2094768

#SPJ4

8 0
1 year ago
A 12.0% sucrose solution by mass has a density of 1.05 gem, what mass of sucrose is present in a 32.0-mL sample of this solution
natulia [17]

Answer:

Option C. 4.03 g

Explanation:

Firstly we analyse data.

12 % by mass, is a sort of concentration. It indicates that in 100 g of SOLUTION, we have 12 g of SOLUTE.

Density is the data that indicates grams of solution in volume of solution.

We need to determine, the volume of solution for the concentration

Density = mass / volume

1.05 g/mL = 100 g / volume

Volume =  100 g / 1.05 g/mL → 95.24 mL

Therefore our 12 g of solute are contained in 95.24 mL

Let's finish this by a rule of three.

95.24 mL contain 12 g of sucrose

Our sample of 32 mL may contain ( 32 . 12) / 95.24 = 4.03 g

7 0
3 years ago
What is the enthalpy of formation (?H?f) of NaHCO3(s) from its constituent elements.
vova2212 [387]

Answer:

Enthalpy of formation = -947.68KJ/mol

Explanation:

Enthalpy of formation is the heat change when one mole of a substance is formed from its element in its standard states and in standard conditions of temperature and pressure. it may be positive or negative, if positive, it is an endothermic reaction where the heat content of the product is greater than that of the reactants, and if negative, it is exothermic reaction - where the heat content of the reactants is greater than the products. the enthalpy of formation is measured in KiloJoule/Moles (KJ/Mole).

From the value of the enthalpy of formation of NaHCO3, it shows that the reaction is exothermic, that is the formation of NaHCO3 from its constituents elements. As such, the heat content of the reactants is greater than the products.

The step by step explanation is shown in the attachment.

7 0
3 years ago
Read 2 more answers
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