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3 years ago

NOBLE GASSES) Why’ are they Inert tho

Chemistry

2 answers:

Reptile [31]3 years ago

8 0

Answer:

i dont know?

Explanation:

why are they?!?!?!?!

igomit [66]3 years ago

5 0

Answer:

Why? Because of electron shells. Technically, they're not fully inert. They have very low reactivity potential, and can only be forced to become reactive with difficulty.

Explanation:

All chemical reactivity is made possible through the atom's electron arrangement. Electrons basically have shelves where they live, called "levels" or "shells". Each level is farther from the nucleus than the previous one. Atoms are most stable when their outer most shell (called the valence shell) is full. Atoms with an incomplete shell will react with other atoms, in an attempt to either fill out the outer shell, or to rid itself of it's valence electrons so that that previous level becomes a full valence level. If the valence shell ils already full, the atom will not be inclined to create compounds.

The first shell can hold up to two electrons. After the first two electrons, any additional electrons have to begin a new shell. The second shell can hold eight electrons before it becomes full. Helium is the first noble gas on the periodic table, having two protons and two electrons. Because helium's outer most shell is full, it does not react with other atoms.

By comparison, look at hydrogen and oxygen. Oxygen has eight electrons. The first two electrons occupy the first shell. The remaining six go to the second shell. This leaves the second shell with two empty spaces that can potentially be filled. Meanwhile, hydrogen has one electron, with it's valence shell having an empty space for one additional electron. Two hydrogen atoms give up their single electrons to an oxygen atom, so that all three end up with stable valence levels.

By the time an atom can fill out the second electron shell on it's own (10 total electrons) you end up with neon, the second noble gas.

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Match the description to the type of mixture.

Softa [21]

Answer:

1-homo

2-hetero

3-hetero

4-homo

Explanation:

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3 years ago

For the reactions below, describe the reactor system and conditions you suggest to maximize the selectivity to make the desired

alexandr1967 [171]

Answer:

hello your question lacks the required reaction pairs below are the missing pairs

Reaction system 1 :

A + B ⇒ D $-r_{1A} = 10exp[-8000K/T]C_{A}C_{B}$

A + B ⇒ U $-r_{2a} = 100exp(-1000K/T)C_{A} ^\frac{1}{2}C_{B} ^\frac{3}{2}$

Reaction system 2

A + B ⇒ D $-r_{1A} = 10exp( -1000K/T)C_{A}C_{B}$

B + D ⇒ U $-r_{2B} = 10^9exp(-10000 K/T) C_{B}C_{D}$

Answer : reaction 1 : description of the reactor system : The desired reaction which is the first reaction possess a higher activation energy and higher temperature is required to kickstart reaction 1

condition to maximize selectivity : To maximize selectivity the concentration of reaction 1 should be higher than that of reaction 2

reaction 2 :

description of reactor system : The desired reaction i.e. reaction 1 has a lower activation energy and lower temperatures is required to kickstart reaction 1

condition to maximize selectivity:

to increase selectivity the concentration of D should be minimal

Explanation:

Reaction system 1 :

A + B ⇒ D $-r_{1A} = 10exp[-8000K/T]C_{A}C_{B}$

A + B ⇒ U $-r_{2a} = 100exp(-1000K/T)C_{A} ^\frac{1}{2}C_{B} ^\frac{3}{2}$

the selectivity of D is represented using the relationship below

$S_{DU} = \frac{-r1A}{-r2A}$

hence SDu = 1/10 * $\frac{exp(-800K/T)}{exp(-1000K/T)} * C_{A} ^{0.5} C_{B} ^{-0.5}$

description of the reactor system : The desired reaction which is the first reaction possess a higher activation energy and higher temperature is required to kickstart reaction 1

condition to maximize selectivity : To maximize selectivity the concentration of reaction 1 should be higher than that of reaction 2

Reaction system 2

A + B ⇒ D $-r_{1A} = 10exp( -1000K/T)C_{A}C_{B}$

B + D ⇒ U $-r_{2B} = 10^9exp(-10000 K/T) C_{B}C_{D}$

selectivity of D

$S_{DU} = \frac{-r1A}{-r2A}$

hence Sdu = $1/10^7 * \frac{exp(-1000K/T)}{exp(-10000K/T)} *\frac{C_{A} }{C_{D} }$

description of reactor system : The desired reaction i.e. reaction 1 has a lower activation energy and lower temperatures is required to kickstart reaction 1

condition to maximize selectivity:

to increase selectivity the concentration of D should be minimal

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Mars2501 [29]

Answer:

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aliya0001 [1]

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Read 2 more answers

Really need help on this thing plz someone... help number 2 and 3:(

olasank [31]

Answer:

I don't have one sorry

Explanation:

it's because I can't see the question I don't know it I'm sorry dude

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3 years ago