Answer:
S= 2(1) = 2
O= 2(4) = 8
Na= 2(2) = 4
Explanation:
The given compound is:
2Na₂SO₄
An element is a distinct substance that cannot be split up into simpler substances.
So;
Number of atoms of elements here are:
S= 2(1) = 2
O= 2(4) = 8
Na= 2(2) = 4
Answer : The ratio of
to
is, 
Solution : Given,

= 0.21 atm
The given equilibrium reaction is,

The expression of
will be,

Now put all the given values in this expression, we get:



Therefore, the ratio of
to
is, 
Answer:
Percent Yield Fe = 82.5%
Explanation:
The actual yield is the value produced after an experiment is conducted. The theoretical yield is the value calculated using the balanced chemical equation and atomic/molar masses.
To find the percent yield of iron (Fe), you need to (1) convert grams Al to moles Al (via atomic mass), then (2) convert moles Al to moles Fe (via mole-to-mole ratio from equation coefficients), then (3) convert moles Fe to grams Fe (via atomic mass), and then (4) calculate the percent yield. It is important to arrange the ratios in a way that allows for the cancellation of units. The final answer should have 3 sig figs to reflect the sig figs of the given values.
Atomic Mass (Mg): 24.305 g/mol
Atomic Mass (Fe): 55.845 g/mol
3 Mg + 2 FeCl₃ -----> 2 Fe + 3 MgCl₂
20.5 g Mg 1 mole 2 moles Fe 55.845 g
----------------- x ----------------- x ---------------------- x ----------------- =
24.305 g 3 moles Mg 1 mole
= 31.4 g Fe
Actual Yield
Percent Yield = ---------------------------------- x 100%
Theoretical Yield
25.9 g Fe
Percent Yield = -------------------- x 100%
31.4 g Fe
Percent Yield = 82.5%
I’m pretty sure it would be B
Answer:
Explanation:
The strong bases have following properties:
1. In solution, strong bases ionize fully.
2. On dissolving the strong bases in water they produce all hydroxide ion which they have.
3. For strong bases the value of equilibrium constant (Kb ) is large.
4. In general the strong base ionizes completely means concentration of ions are greater means conductivity also greater.
5. For strong bases the value of equilibrium constant (Kb) is large, thus the value of dG0 is very large negative number.