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Crank
3 years ago
11

A homeowner has a new oil furnace which has an efficiency of 60%. For every 100 barrels of oil used to heat his house, how much

(in barrels of oil) goes up the chimney as waste heat?
Physics
1 answer:
nasty-shy [4]3 years ago
4 0

Answer:

below

Explanation:

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Which of these can Waves transfer energy through?
professor190 [17]
Hey which type of wave are u talking about a sound wave a electromagnetic one ?
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3 years ago
What additional steps might be included in the eap for a wave pool, a winding river and the landing zone of a speed slide?
liubo4ka [24]

Explanation:

Following are the steps taken

1. To turn off the wave in the wave pool press the emergency turn off button (E-stop).

2. Winding of river or shutting off flow of water in the slide.

3. Dispatch of riders at speed slide is stopped.

6 0
3 years ago
Aril does 1800 J of work to get a canoe moving from rest. April and the canoe have a mass of 70 kg.
wolverine [178]

a) KE=energy required to make them move=1800J

b) KE=1/2*mv^2, so v=\sqrt{\frac{2KE}{m}}=7.17 J

4 0
3 years ago
Read 2 more answers
Two billiard balls of equal mass move at right angles and meet at the origin of an xy coordinate system. Initially ball A is mov
frez [133]

Answer:

Speed of ball A after collision is 3.7 m/s

Speed of ball B after collision is 2 m/s

Direction of ball A after collision is towards positive x axis

Total momentum after collision is m×4·21 kgm/s

Total kinetic energy after collision is m×8·85 J

Explanation:

<h3>If we consider two balls as a system as there is no external force initial momentum of the system must be equal to the final momentum of the system</h3>

Let the mass of each ball be m kg

v_{1} be the velocity of ball A along positive x axis

v_{2} be the velocity of ball A along positive y axis

u be the velocity of ball B along positive y axis

Conservation of momentum along x axis

m×3·7 = m× v_{1}

∴  v_{1} = 3.7 m/s along positive x axis

Conservation of momentum along y axis

m×2 = m×u + m× v_{2}

2 = u +  v_{2} → equation 1

<h3>Assuming that there is no permanent deformation between the balls we can say that it is an elastic collision</h3><h3>And for an elastic collision, coefficient of restitution = 1</h3>

∴ relative velocity of approach = relative velocity of separation

-2 =  v_{2} - u → equation 2

By adding both equations 1 and 2 we get

v_{2} = 0

∴ u = 2 m/s along positive y axis

Kinetic energy before collision and after collision remains constant because it is an elastic collision

Kinetic energy = (m×2² + m×3·7²)÷2

                         = 8·85×m J

Total momentum = m×√(2² + 3·7²)

                             = m× 4·21 kgm/s

3 0
4 years ago
A ball was dropped from a height of 10 feet. Each time it hits the ground, it bounces 4/5 of its previous height. Find the total
Shtirlitz [24]

Answer:

d = 90 ft

Explanation:

As we know that after each bounce it reaches to 4/5 times of initial height

so we can say

h_2 = \frac{4}{5}h

so the distance covered is given as

d = h + 2(\frac{4}{5}h) + 2(\frac{4}{5})^2h + 2(\frac{4}{5})^3h........

here we know that

h = 10 feet

d = h + 2(\frac{4}{5}h)(1 + \frac{4}{5} + (\frac{4}{5})^2 + ...........)

d = 10 + 2(\frac{4}{5}(10))(\frac{1}{1 - \frac{4}{5}})

d = 90 ft

8 0
3 years ago
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