The similarity between a car at rest and a car moving at constant velocity is that the both cars have zero acceleration. the car at rest is not moving so its acceleration should also be zero. for the car at constant velocity, since the velocity of the car is not changing, and acceleration is change in velocity per time, that it why it is also zero
current . . . flow of electric charges
voltage . . . stored potential energy at the source of a circuit
resistance . . . opposition to the flow of electric current
arrowRight . . . a button on the computer keyboard that causes the cursor to move to the right on the screen when pushed
arrowRight . . . a button on the computer keyboard that causes the cursor to move to the right on the screen when pushed
arrowRight . . . a button on the computer keyboard that causes the cursor to move to the right on the screen when pushed
Second question: tensional stress causes fractures to occur in the lithosphere.
Answer:
M₂ = M then L₂ = L
M₂> M then L₂ = \frac{M}{M_{2}} L
Explanation:
This is a static equilibrium exercise, to solve it we must fix a reference system at the turning point, generally in the center of the rod. By convention counterclockwise turns are considered positive
∑ τ = 0
The mass of the rock is M and placed at a distance, L the mass of the rod M₁, is considered to be placed in its center of mass, which by uniform e is in its geometric center (x = 0) and the triangular mass M₂, with a distance L₂
The triangular shape of the second object determines that its mass can be considered concentrated in its geometric center (median) that tapers with a vertical line if the triangle is equilateral, the most used shape in measurements.
M L + M₁ 0 - m₂ L₂ = 0
M L - m₂ L₂ = 0
L₂ = L
From this answer we have several possibilities
* if the two masses are equal then L₂ = L
* If the masses are different, with M₂> M then L₂ = \frac{M}{M_{2}} L