Answer:
the time of motion of the ball is 6.89 ms.
Explanation:
Given;
angular speed, ω = 38 rad/s
angular distance, θ = 15 degrees
Angular distance in radian;
Time of motion is calculated as;
Therefore, the time of motion of the ball is 6.89 ms.
A projectile<span> is an object upon which the only force acting is gravity. Many </span>projectiles<span> not only undergo a vertical </span>motion<span>, but also undergo a horizontal </span>motion<span>. That is, as they move upward or downward they are also moving horizontally.</span>
F=mv^2/R
----> V^2=FR/m=(350x0.9)/2.5=126
----- V=11.22 m/s
Answer:
33.2 m
Explanation:
For the first object:
y₀ = 81.5 m
v₀ = 0 m/s
a = -9.8 m/s²
t₀ = 0 s
y = y₀ + v₀ t + ½ at²
y = 81.5 − 4.9t²
For the second object:
y₀ = 0 m
v₀ = 40.0 m/s
a = -9.8 m/s²
t₀ = 2.20 s
y = y₀ + v₀ t + ½ at²
y = 40(t−2.2) − 4.9(t−2.2)²
When they meet:
81.5 − 4.9t² = 40(t−2.2) − 4.9(t−2.2)²
81.5 − 4.9t² = 40t − 88 − 4.9 (t² − 4.4t + 4.84)
81.5 − 4.9t² = 40t − 88 − 4.9t² + 21.56t − 23.716
81.5 = 61.56t − 111.716
193.216 = 61.56t
t = 3.139
The position at that time is:
y = 81.5 − 4.9(3.139)²
y = 33.2
O.99 m long .simple pendulum time period is 2s for second formula then use formula T=2pi.rt(lenght/gravity)
