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2 years ago

Why does the layer of glass in a solar cell need an antireflective coating?

Physics

2 answers:

Lera25 [3.4K]2 years ago

5 0

Answer:

The Anti Reflective Coating on a solar cells helps to increase the amount of light absorbed into the cell. This anti reflective coating is very much needed as the reflection of a bare silicon solar cells is over 30%. For the thin AR Coating, silicon nitride or titanium oxide is used.

Explanation:

hope this help:)

ruslelena [56]2 years ago

3 0

A. To maximize the energy absorbed by the solar cell

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D because those are both concerning.

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3 years ago

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Explanation: There are a couple of ways to use velocity in an equation in the photo.

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2 years ago

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Ann [662]

3-6 seconds time interval is the object slowing down.

The correct option is C.

<h3>What is a time interval?</h3>

The time interval is the span of time among two specified times. To put it another way, it is the amount of time that has passed between the event's start and finish.

<h3>What are different time intervals?</h3>

The time interval is the length of time that the aim uses to gather data and determine values. The critical overview can be one or more seconds, minutes, hours, days, weeks, or months. The period must be greater than zero and positive. When providing minutes, the amount of minutes must divide evenly by 60.

To know more about Time interval visit:

brainly.com/question/28238258

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The complete question is -

During which time interval is the object slowing down ?

a- 8-10 seconds

b- 6-8 seconds

c- 3-6 seconds

d- 0-3 seconds

4 0

1 year ago

A +1.0 nC charge is at x = 0 cm, a -1.0 nC charge is at x = 1.0 cm and a 4.0 nC at x= 2 cm. What is the electric potential energ

lesantik [10]

Answer:

- 2.7 x 10^-6 J

Explanation:

q1 = 1 nC at x = 0 cm

q2 = - 1 nC at x = 1 cm

q3 = 4 nC at x = 2 cm

The formula for the potential energy between the two charges is given by

$U=\frac{Kq_{1}q_{2}}{r}$

where r be the distance between the two charges

By use of superposition principle, the total energy of the system is given by

$U = U_{1,2}+U_{2,3}+U_{3,1}$

$U=\frac{Kq_{1}q_{2}}{0.01}+\frac{Kq_{2}q_{3}}{0.01}+\frac{Kq_{3}q_{1}}{0.02}$

$U=-\frac{9\times10^{9}\times 1\times10^{-9}\times 1\times10^{-9}}}{0.01}-\frac{9\times10^{9}\times 1\times10^{-9}\times 4\times10^{-9}}}{0.01}+-\frac{9\times10^{9}\times 1\times10^{-9}\times 4\times10^{-9}}}{0.02}$

U = - 2.7 x 10^-6 J

3 0

3 years ago

How much work is done (by a battery, generator, or some other source of potential difference) in moving Avogadro's number of ele

luda_lava [24]

Answer:

W = 1.5 x 10⁶ J = 1.5 MJ

Explanation:

First, we calculate the potential difference between the given 2 points. So, we have:

V₁ = Electric Potential at Initial Position = 6.7 V

V₂ = Electric Potential at Final Position = - 8.9 V

Therefore,

ΔV = Potential Difference = V₂ - V₁ = -8.9 V - 6.7 V = - 15.6 V

Since, we use magnitude in calculation only. Therefore,

ΔV = 15.6 V

Now, we calculate total charge:

Total Charge = q = (No. of Electrons)(Charge on 1 Electron)

where,

No. of Electrons = Avagadro's No. = 6.022 x 10²³

Charge on 1 electron = 1.6 x 10⁻¹⁹ C

Therefore,

q = (6.022 x 10²³)(1.6 x 10⁻¹⁹ C)

q = 96352 C

Now, from the definition of potential difference, we know that it is equal to the worked done on a unit charge moving it between the two points of different potentials:

ΔV = W/q

W = (ΔV )(q)

where,

W = work done = ?

W = (15.6 V)(96352 C)

7 0

3 years ago