Question

If the pressure of gas is doubled and its absolute temperature is quadrupled, the volume is what factor times the original?

Answer 1

Answer:

Volume will increase by factor 2

So option (A) will be correct answer  

Explanation:

Let initially the volume is V pressure is P and temperature is T

According to ideal gas equation $PV=nRT$, here n is number of moles and R is gas constant

So $V=\frac{nRT}{P}$....................eqn 1

Now pressure is doubled and temperature is quadrupled

So new volume $V_{new}=\frac{nR4T}{2P}=\frac{2nRT}{P}$ ........eqn 2

Now comparing eqn 1 nad eqn 2

$V_{new}=2V$

So volume will increase by factor 2

So option (A) will be correct answer