Answer:
Explanation:
In this, we can with the <u>ionization equation</u> for the hydrazoic acid (). So:
Now, due to the Ka constant value, we have to use the whole equilibrium because this <u>is not a strong acid</u>. So, we have to write the <u>Ka expression</u>:
For each mol of produced we will have 1 mol of . So, we can use <u>"X" for the unknown</u> values and replace in the Ka equation:
Additionally, we have to keep in mind that is a reagent, this means that we will be <u>consumed</u>. We dont know how much acid would be consumed but we can express a<u> subtraction from the initial value</u>, so:
Finally, we can put the ka value and <u>solve for "X"</u>:
So, we have a concentration of 0.000285 for . With this in mind, we can calculate the <u>pH value</u>:
I hope it helps!
Answer:
Carbon dioxide serves as the source of carbon,
Explanation:
Answer: The concentration of Silver Nitrate in solution # 4 is 3.5x10-6 M
Explanation:
When calculating the concentration of a dilute solution, we use the equation:
C1V1 = C2V2
Where C1 = concentration of the known solution
V1= amount of know solution
C2= new concentration
V2= capacity of the flask
Keep in mind that solution #2 is not related to the preparation of solutions #3 y #4, so the concentration of #2 is irrelevant.
For calculating the concentration of solution #4 , we first calculate the concentration of the solution #3, that comes from the solution #1.
- Calculating concentration solution #3
- C1V1 = C3V3
- C3= (0.0002442 M * 10mL) / 250mL
- C3= 9.8X10-6M
2. Calculating concentration solution #4
- C3V3 = C4V4
- C4= (9.8X10-6M *18mL) / 50mL
- C4= 3.5X10-6 M
Answer:
True
Explanation:
Molecular mass of :
Molecular mass of Ca + molevular mass of C + molecular mass of O × 3
40g + 12g + 16 × 3g
= 40g + 60 = 100g
Thus its true
I don’t see a 2+. If you’re talking about the number next to your cursor, it’s a 23.