Answer:
The rate of disappearance of C₂H₆O = 2.46 mol/min
Explanation:
The equation of the reaction is given below:
2 K₂Cr₂O₇ + 8 H₂SO₄ + 3 C₂H₆O → 2 Cr₂(SO₄)₃ + 2 K₂SO₄ + 11 H₂O
From the equation of the reaction, 3 moles of C₂H₆O is used when 2 moles of Cr₂(SO₄)₃ are produced, therefore, the mole ratio of C₂H₆O to Cr₂(SO₄)₃ is 3:2.
The rate of appearance of Cr₂(SO₄)₃ in that particular moment is given 1.64 mol/min. This would than means that C₂H₆O must be used up at a rate which is approximately equal to their mole ratios. Thus, the rate of of the disappearance of C₂H₆O can be calculated from the mole ratio of Cr₂(SO₄)₃ and C₂H₆O.
Rate of disappearance of C₂H₆O = 1.64 mol/min of Cr₂(SO₄)₃ * 3 moles of C₂H₆O / 2 moles of Cr₂(SO₄)₃
Rate of disappearance of C₂H₆O = 2.46 mol/min of C₂H₆O
Therefore, the rate of disappearance of C₂H₆O = 2.46 mol/min
Answer:
A hypothesis is something you can test a theory is just a thought that you have.
- The student weighs out 0.0422 grams of the metal magnesium, thus we can figure that the more's, the magnesium he used, is the mass of the magnesium over the more mass, which is 0.024422.
- That is approximately 0.001758.
- Furthermore, it claims that too much hydrochloric acid causes the metal magnesium to react, producing hydrogen gas.
- The volume of collected gas is 43.9 cc, the mastic pressure is 22 cc, and a sample of hydrogen gas is collected over water in a meter.
<h3>Is it true that calculations made utilizing experimental and gathered data result in a percent error? </h3>
- Consequently, we are aware that magnesium and chloride react.
- We create 1 as the reaction ratio is 1:2.
- The hydrogen and 1 are more.
- Magnesium chloride is more.
- Therefore, based on this equation, we can infer that the amount of hydrogen that would be created in this scenario is greater than the amount of magnesium present here, or 0.001758 more.
- Among hydrogen, there is.
- \Once we convert the temperature from 32 Celsius to kelvin, we can tell you that the temperature is actually about 5.15 kelvin.
- The gas has a volume of 43 in m, which is equal to 0.0439 liter and indicates that the pressure is approximately 832 millimeter.
- Mercury, which is 2 times 13332 plus ca, or roughly 110922.24 par, is a mathematical constant.
- So, in this instance, we are aware that p v = n r t.
- The r in this case equals p v over n t, thus we want to determine the r.
- So p is 110922.24. The temperature is 305.15 and the V is 0.04 over the n is 0.001758.
- Let's proceed with the calculations right now.
- In this instance, you will discover that the solution is 9.077 times 10; that is all there is to it.
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Answer:
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